Draw line-angle structures for the compounds (a) through (h). g. (CH 3 CH 2 ) 2 CO h. (CH 3 ) 3 COH

Welcome back, everyone provide the line angle structures of the following compounds. Let's begin with the first compound. And one of the ways to easily draw line angle structures is to, first of all think what it could be. Well, essentially the first structure has a prop group in parent C and we have two times prop group, meaning there will be two prop groups bonded to the carbon from CEO. And since that carbon must have four bonds, we already see two ethyl groups bonded to it as a result, co must be carbona because there must be a double bond between carbon and oxygen. So what we're going to do is first of all realize that this is a form of a ketone Rcor, it's simply written as R to co, what we can do is first we draw that Carbel group. So we want to draw co double bonded and now we have those two propel groups, bonnet t carbonel carbon. So we're going to add three carbons on the left, we have one, two and three, right, essentially each vertex in each corner represents an implicit carbon. So we have 123 carbon atoms bonded to co and then on the right side of co, we want to do the same, we want to draw a total of three carbon atoms, the 12 and three. Well, then we have our first structure and we can move on to the second one. What about this structure? Well, essentially it has a proper group multiplied by three in parentheses bonded to Coh. So in this case, we have three groups bonnet to a central carbon sea and that sees bonded to. Oh, so that would be an alcohol specifically, we have a form R three Coh. Whenever carbon is born at Coh, it is an alcohol, right? So what we can do is this draw that o age bonded to carbon, right? And then that carbon is bonded to three equivalent propel groups. So we're just drawing one to wee carbon atoms. Now, for the second pro group, we have one, two and three carbon atoms. And finally, we are going to do the same for the remaining part, 12 and three carbon atoms. So once again, we have three prop groups bonded to the central carbon. That is B 20 which is hydroxyl. And that's how we get our answers. Thank you for watching.

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1. A Review of General Chemistry5h 5m
2. Molecular Representations1h 14m
3. Acids and Bases2h 46m
4. Alkanes and Cycloalkanes4h 17m
5. Chirality3h 39m
6. Thermodynamics and Kinetics1h 22m
7. Substitution Reactions1h 48m
8. Elimination Reactions2h 30m
9. Alkenes and Alkynes2h 9m
10. Addition Reactions3h 19m
11. Radical Reactions1h 58m
12. Alcohols, Ethers, Epoxides and Thiols2h 42m
13. Alcohols and Carbonyl Compounds2h 17m
14. Synthetic Techniques1h 26m
15. Analytical Techniques:IR, NMR, Mass Spect7h 3m
16. Conjugated Systems6h 13m
17. Ultraviolet Spectroscopy51m
18. Aromaticity2h 34m
19. Reactions of Aromatics: EAS and Beyond5h 1m
20. Phenols55m
21. Aldehydes and Ketones: Nucleophilic Addition4h 56m
22. Carboxylic Acid Derivatives: NAS2h 51m
23. The Chemistry of Thioesters, Phophate Ester and Phosphate Anhydrides1h 10m
24. Enolate Chemistry: Reactions at the Alpha-Carbon1h 53m
25. Condensation Chemistry2h 9m
26. Amines1h 43m
27. Heterocycles2h 0m
28. Carbohydrates5h 53m
29. Amino Acids4h 20m
30. Peptides and Proteins2h 42m
31. Catalysis in Organic Reactions1h 30m
32. Lipids 2h 50m
33. The Organic Chemistry of Metabolic Pathways2h 52m
34. Nucleic Acids1h 32m
35. Transition Metals6h 14m
36. Synthetic Polymers1h 49m

1. A Review of General Chemistry

Condensed Structural Formula

Organic Chemistry

1. A Review of General Chemistry

Condensed Structural Formula

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3:24 minutes

Problem 13g,h

Textbook Question

Draw line-angle structures for the compounds (a) through (h).
g. (CH₃CH₂)₂CO
h. (CH₃)₃COH

Verified step by step guidance

Identify the molecular formula for each compound. For example, (CH3CH2)2CO is diethyl ketone, and (CH3)3COH is tert-butyl alcohol.

For (CH3CH2)2CO, recognize that it is a ketone with two ethyl groups attached to the carbonyl carbon. The structure will have a central carbon double-bonded to oxygen (C=O) with two ethyl groups (CH3CH2-) attached to the central carbon.

Draw the line-angle structure for (CH3CH2)2CO: Start with the carbonyl group (C=O) and attach two lines representing the ethyl groups. Each line represents a bond, and the ends of the lines represent carbon atoms.

For (CH3)3COH, recognize that it is an alcohol with a tert-butyl group attached to the hydroxyl group. The structure will have a central carbon bonded to three methyl groups (CH3-) and one hydroxyl group (OH).

Draw the line-angle structure for (CH3)3COH: Start with a central carbon atom, attach three lines for the methyl groups, and one line for the hydroxyl group. The lines for the methyl groups should branch out from the central carbon, and the hydroxyl group should be represented by a line ending with an OH group.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Line-Angle Structures

Line-angle structures, also known as skeletal formulas, are a simplified representation of organic molecules where lines represent chemical bonds and vertices represent carbon atoms. Hydrogen atoms attached to carbons are typically omitted for clarity, while other atoms are explicitly shown. This method is efficient for visualizing complex organic compounds.

Functional Groups

Functional groups are specific groups of atoms within molecules that are responsible for the characteristic chemical reactions of those molecules. In the given compounds, the carbonyl group (C=O) in (CH3CH2)2CO and the hydroxyl group (OH) in (CH3)3COH are key functional groups that define the chemical behavior and properties of these compounds.

Isomerism

Isomerism refers to the phenomenon where compounds have the same molecular formula but different structural arrangements. Understanding isomerism is crucial for drawing line-angle structures, as it helps in identifying the correct spatial arrangement of atoms. In the given compounds, recognizing the arrangement of alkyl groups around the functional groups is essential for accurate representation.

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