Draw a line-angle formula for each compound. a. CH 3 COCH 2 CHCHCOOH b. NCCH 2 COCH 2 CHO

Welcome back, everyone provide the line angle structures for the molecules listed below. Let's begin with the first one. It says HCO. So we can just draw H bonded to carbon because Hygen can make one bond, carbon will make four bonds and auction will make two bonds. So we have HC followed by ch let's recall that we are trying to bond carbons together, right? So if we are seeing HCO, then bonnet to see if carbon needs to have more bonds, we as simply one to throw an additional bond between carbon and oxygen because oxygen also needs two burns. So we have HC, that's our aldehyde group followed by S two. So we're going to draw siege two, followed by another siege too. And then we have Chch. Now, what do we understand? Well, essentially those carbons have three bonds only. So we want to introduce a double bond between them. And finally, coo H now, coo H is a carboxyl group. So we're just going to draw a double bond between carbon and oxygen and the remaining oxygen will have hydrogen bonded. It just as shown. And now, if we want to get a line angle formula, we can draw that aldehyde group. We're just going to hide all of those hydrogens and carbons. So let's draw the aldehyde group. We have carbonel. We want to show that hydrogen for the aldehyde because that's a convention such that we can recognize the aldehyde more easily. And then we can just count the number of carbon atoms that we have in the stray chain 123456. So we have 12, 34, five and six and that sixth one is born at co, we're going to throw a double bond or oxygen. And also we want to add the remaining double bond that we had. Well, then we have our structure with all of the implicit hygen not shown that are bonded to carbons. We're only showing hydrogens bonded to oxygen and specifically that for the aldehyde right now, let's consider the second structure. And it says we have siege three B to CEO bonded to CH two. And what we immediately noticed is that carbon is missing one bond, also oxygen is missing that bond. We're introducing a double bond. And then it says siege too, followed by ch in parentheses, we have CN, which means that this substitution is bonded to C carbon. And now we want to recall that CN essential, we'll have a triple bond because carbon needs four bonds and nitrogen needs three. And finally see show we already know what it is. It's the aldehyde group And now if we convert it into a bond line structure, we want to count carbons 123, 45. So let's draw five carbon atoms in the zigzag chain. We have siege three followed by the kanno group or by siege to ch that is bonded to night trial. So we can just essentially indicate cm triple bond. However, for bond line structures, this is not required, right? We do not necessarily need to show those bonds. We can just say CN, right. That's simpler. And finally, CM Bonnet CC is followed by the aldehyde group. That's it. We have our structure Sam. Thank you for watching.

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1. A Review of General Chemistry5h 5m
2. Molecular Representations1h 14m
3. Acids and Bases2h 46m
4. Alkanes and Cycloalkanes4h 17m
5. Chirality3h 39m
6. Thermodynamics and Kinetics1h 22m
7. Substitution Reactions1h 48m
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13. Alcohols and Carbonyl Compounds2h 17m
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21. Aldehydes and Ketones: Nucleophilic Addition4h 56m
22. Carboxylic Acid Derivatives: NAS2h 51m
23. The Chemistry of Thioesters, Phophate Ester and Phosphate Anhydrides1h 10m
24. Enolate Chemistry: Reactions at the Alpha-Carbon1h 53m
25. Condensation Chemistry2h 9m
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31. Catalysis in Organic Reactions1h 30m
32. Lipids 2h 50m
33. The Organic Chemistry of Metabolic Pathways2h 52m
34. Nucleic Acids1h 32m
35. Transition Metals6h 14m
36. Synthetic Polymers1h 49m

1. A Review of General Chemistry

Condensed Structural Formula

Organic Chemistry

1. A Review of General Chemistry

Condensed Structural Formula

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5:32 minutes

Problem 33a,b

Textbook Question

Draw a line-angle formula for each compound.
a. CH₃COCH₂CHCHCOOH
b. NCCH₂COCH₂CHO

Verified step by step guidance

Identify the functional groups in each compound. For compound (a), CH3COCH2CHCHCOOH, note the presence of a ketone (CO), a carboxylic acid (COOH), and a double bond (CH=CH). For compound (b), NCCH2COCH2CHO, identify the nitrile (NC), ketone (CO), and aldehyde (CHO) groups.

For compound (a), start by drawing the longest carbon chain. The backbone consists of six carbon atoms. Use a zigzag line to represent the carbon chain, with each vertex representing a carbon atom.

Add the functional groups to the carbon chain for compound (a). Place the ketone group (C=O) on the second carbon, the double bond between the fourth and fifth carbons, and the carboxylic acid (COOH) at the end of the chain.

For compound (b), draw the longest carbon chain, which consists of five carbon atoms. Again, use a zigzag line to represent the carbon chain.

Add the functional groups to the carbon chain for compound (b). Place the nitrile group (C≡N) at the beginning of the chain, the ketone group (C=O) on the third carbon, and the aldehyde group (CHO) at the end of the chain.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Line-Angle Formula

The line-angle formula, also known as skeletal structure, is a simplified representation of organic molecules. In this notation, carbon atoms are represented as vertices or ends of lines, and hydrogen atoms attached to carbons are usually omitted. This method highlights the carbon skeleton and functional groups, making it easier to visualize complex organic structures.

Functional Groups

Functional groups are specific groups of atoms within molecules that have characteristic properties and reactivity. In organic chemistry, recognizing functional groups like ketones (C=O), carboxylic acids (COOH), and nitriles (CN) is crucial for understanding the chemical behavior of compounds. They determine the molecule's reactivity and interactions with other substances.

Molecular Geometry

Molecular geometry refers to the three-dimensional arrangement of atoms within a molecule. Understanding the geometry is essential for drawing accurate line-angle formulas, as it affects the molecule's shape and properties. For example, knowing that carbon typically forms four bonds in a tetrahedral arrangement helps in correctly positioning atoms and bonds in the skeletal structure.

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