Draw a line-angle formula for each compound. c. CH 2 CHCH(OH)CH 2 CO 2 H d. CH 2 CHC(CH 3 )CHCOOCH 3

Hey everyone, let's do this problem. It says write the appropriate line angle structure for each of the following compounds. We have H. O. Ch two Ch two, C. 00. H. And ch two ch ch ch C. 00 ch three. So first before we start drawing we're going to break down the name, identify the functional groups that we have. Just so we already get a mental image of what we're going to draw. Then we're going to start drawing our compound by connecting the non hydrogen atoms from left to right. Then we're going to add the hydrogen to their respective adam. So you're usually adding the hydrogen to the atom written before it. Unless it's an ending like this one we have the H. Before the oh but since it's it's an ending it has nowhere else to go. So it's going to be on that H. Then we're going to redraw our structure in a zigzag form. And lastly we're going to remove the carbon and hydrogen so that we can have a bond line structure. Okay so let's apply these steps to our two structures. First we have H. O. C. H two C H two C. 00. H. Okay so the functional groups that we have here on this ending, we have C. 00. H. That's a carb oxalic acid on the other end, we have O. H which is an alcohol group and in between we have CH two CH 2 which is simply al caine chain. Alright so let's draw our non hydrogen atoms. So we have oxygen carbon carbon, carbon, oxygen, oxygen. But we know how our carb oxalic acid functional group looks like right C double bond oh single bonded O. H. So let's draw oxygen. Carbon carbon carbon double bond O. Single bond. Oh now we'll add our hydrogen. So hydrogen here two Hydrogen is to our carbons in a hydrogen to our carb oxalic acid over here. Okay so now let's do make it a zigzag and I won't draw these hydrogen for now because we're just going to remove them. So let's remove all the carbons and hydrogen except we're not removing the hydrogen on the oxygen's right? Only on the carbons because we still need our functional groups there. Alright, so that is our bond line line angle structure. Now let's do the next one. Oops. Now we have CH two C H C H C H COOCH three. All right, so CH two ch ch ch I noticed that these carbons are not fully substituted. So this is going to be an alc in right? Some of those hydrogen are missing. So there's going to be some double bonds here. Then we have C. 00. Ch three. So this isn't our group. This isn't our group. So we have our O. R. And that is an ester. Okay, so let's draw this out with our non hydrogen atoms. So 12345 carbons. Then we have our double bonnet oxygen single bonded oxygen both to that same carbon and our last carbon on the end. So 12345 carbons double bond, oh oh and then our methyl group. So now we'll add the hydrogen, two hydrogen on this end, carbon one hydrogen on the central carbons And 300 gens on this end methyl group. So we know that there has to be some Elkins here. So let's add some double bonds to complete the octet of these carbons. So we'll have one between carbons, one and 21 between carbons three and four. And that is it. So let's convert this to zigzag. So we have 123, 45 carbons in a double bond oxygen on that fifth carbon, single bond oxygen in a methyl group. So we're going to now remove those carbons to have our line angle formula. So 12345 double bond oxygen, O metal. Alright, so that is your line angle structure for the second one. And these structures leave you with a to be the correct answer. That's it for this problem. I hope this video is helpful and thanks for watching

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1. A Review of General Chemistry5h 5m
2. Molecular Representations1h 14m
3. Acids and Bases2h 46m
4. Alkanes and Cycloalkanes4h 17m
5. Chirality3h 39m
6. Thermodynamics and Kinetics1h 22m
7. Substitution Reactions1h 48m
8. Elimination Reactions2h 30m
9. Alkenes and Alkynes2h 9m
10. Addition Reactions3h 19m
11. Radical Reactions1h 58m
12. Alcohols, Ethers, Epoxides and Thiols2h 42m
13. Alcohols and Carbonyl Compounds2h 17m
14. Synthetic Techniques1h 26m
15. Analytical Techniques:IR, NMR, Mass Spect7h 3m
16. Conjugated Systems6h 13m
17. Ultraviolet Spectroscopy51m
18. Aromaticity2h 34m
19. Reactions of Aromatics: EAS and Beyond5h 1m
20. Phenols55m
21. Aldehydes and Ketones: Nucleophilic Addition4h 56m
22. Carboxylic Acid Derivatives: NAS2h 51m
23. The Chemistry of Thioesters, Phophate Ester and Phosphate Anhydrides1h 10m
24. Enolate Chemistry: Reactions at the Alpha-Carbon1h 53m
25. Condensation Chemistry2h 9m
26. Amines1h 43m
27. Heterocycles2h 0m
28. Carbohydrates5h 53m
29. Amino Acids4h 20m
30. Peptides and Proteins2h 42m
31. Catalysis in Organic Reactions1h 30m
32. Lipids 2h 50m
33. The Organic Chemistry of Metabolic Pathways2h 52m
34. Nucleic Acids1h 32m
35. Transition Metals6h 14m
36. Synthetic Polymers1h 49m

1. A Review of General Chemistry

Condensed Structural Formula

Organic Chemistry

1. A Review of General Chemistry

Condensed Structural Formula

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6:20 minutes

Problem 33c,d

Textbook Question

Draw a line-angle formula for each compound.
c. CH₂CHCH(OH)CH₂CO₂H
d. CH₂CHC(CH₃)CHCOOCH₃

Verified step by step guidance

Step 1: Understand the line-angle formula representation. In organic chemistry, a line-angle formula is a simplified way to depict molecular structures. Each vertex represents a carbon atom, and lines represent bonds between them. Hydrogen atoms attached to carbons are usually omitted for simplicity.

Step 2: Analyze the compound H2CHCH(OH)CH2CO2H. Start by identifying the main carbon chain and functional groups. The main chain consists of five carbon atoms. The functional groups are an alcohol (OH) and a carboxylic acid (CO2H).

Step 3: Draw the backbone of the compound H2CHCH(OH)CH2CO2H. Begin with a zigzag line representing the carbon chain. Place the OH group on the second carbon and the CO2H group on the fifth carbon.

Step 4: Analyze the compound CH2CHC(CH3)CHCOOCH3. Identify the main carbon chain and functional groups. The main chain consists of five carbon atoms. The functional groups are a methyl group (CH3) and an ester (COOCH3).

Step 5: Draw the backbone of the compound CH2CHC(CH3)CHCOOCH3. Start with a zigzag line for the carbon chain. Place the CH3 group on the third carbon and the COOCH3 group on the fifth carbon. Ensure the correct placement of double bonds if indicated by the structure.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Line-Angle Formula

The line-angle formula, also known as skeletal structure, is a simplified representation of organic molecules. In this notation, carbon atoms are represented as vertices or ends of lines, and hydrogen atoms attached to carbons are usually omitted. This method highlights the carbon skeleton and functional groups, making it easier to visualize complex organic structures.

Functional Groups

Functional groups are specific groups of atoms within molecules that have characteristic properties and reactivity. In organic chemistry, recognizing functional groups like alcohols (OH), carboxylic acids (CO2H), and esters (COOCH3) is crucial for understanding the chemical behavior of compounds. Each functional group imparts distinct physical and chemical properties to the molecule.

IUPAC Nomenclature

IUPAC nomenclature is a systematic method of naming organic chemical compounds as recommended by the International Union of Pure and Applied Chemistry. It provides a standardized way to name compounds based on their structure, ensuring clear communication. Understanding IUPAC rules helps in identifying the structure from a name and vice versa, which is essential for drawing line-angle formulas.

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