Draw line-angle structures for the compounds (a) through (h). c. CH 3 CH 2 COCN d. CH 2 CHCHO

Hey everyone, let's solve this problem. It reads show how to draw a line angle structures corresponding to the following condensed formulas. So before we jump into drawing our line angle structures, which if you recall are just skeletal structures that show the connectivity of our atoms. We have to remember some important things about our best friend carbon is that in our skeletal structures, carbon represents all the corners and the ends and also that we need four bonds and that carbon to make her happy. Okay, so that means whether it's an unspoken or implied hydrogen that are on that carbon or another group that we're drawing on it, it has to have four bonds. So if you keep these things in mind, you will definitely be set up for success when drawing these out. So let's jump in our first condensed formula is CH three, CH two, CH two, C O N H two. Okay, so first I like to count the carbons that I have 1234, just to get an idea of how long my carbon my alcohol chain will be. And I also like to kind of break it down into any familiar groups I have because as you do these more and more, you'll start to see patterns. So here I see I have a CH three, which is a methyl group and that is always going to be an ending on our chain. So either the end of a chain or a substitution group. So that's going to be an ending, then I have to see H2s and that's important because when you draw an alcohol chain, say, I have a long chain. That's kind of ugly. But these are all gonna be CH two CH two CH two CH two. So, if you see a bunch of repeating CH two, it's kind of easy to imagine it in your head because you just picture that repeating alcohol chain chain chain. All right. Brownie points. If you know who sings that song. So, I have my two CH two chainz and then I have C. O. NH two. This might not look familiar yet. But if you're reviewing, if you already learned functional groups and you're reviewing, you should know this isn't a mind ending. And let's get into drawing this. So, we have our four carbons. So, I'll have my four. My chain four carbons 1234. And let's see how these last few groups are going to be connected. I have this carbon is connected to that previous carbon Over here and I see an O. In an N. How many bonds is that? You're right. That's only three. And what do we know about our friend carbon? She wants four bonds. So, I think we're going to have a double bond on one of those atoms. And I think it's going to be oxygen. Hmm. Do you think this is right? Is my nitrogen happy with three bonds? Yes, it is just like carbon is happy with four. We recall from general chemistry that nitrogen is happy with three bonds. So this will be our structure. All right, great job guys. Next one. We have CH three C O. Ch three short and sweet. So I'm going to do the same thing. Let's see. We have 123 carbons on our chain. 123. And let's just break this up into groups. I have my method ending method lending. And as you get more familiar with these, you don't have to write this out. You just kind of mentally check these things. But I'm writing it out to show you guys sort of that thought process. And then I have a C. O. Which is going to be a ketone functional group and that's an inside or an internal is a better word. Internal carbon steel. Which if you haven't learned about that yet, it's OK. That just means we have a C double bond. Oh, group in the middle of an alcohol chain. Okay. It's not on the end, it's in the middle, that's why it's internal. And how do we know? So let's draw that double bond O on our second carbon. How do we know it's a double bond? Let's check for our four bonds. I have C to that first methyl carbon, see to that second methyl carbon, that's only two bonds. So I need two more. And guess where they're coming from that oxygen. Okay, so that's how we know that it is carbon double bond. Oh and some or go trivia for you. This is actually called acetone. And don't worry, you might not have to know that yet. You might not ever have to memorize that. But by at some point in your or go course, your teacher will probably expect you to recognize that this is acetone. So I'll just mention that now, since we have just learned how to recognize the condensed formula and draw the structure, I hope this is helpful. And thanks for watching.

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1. A Review of General Chemistry5h 5m
2. Molecular Representations1h 14m
3. Acids and Bases2h 46m
4. Alkanes and Cycloalkanes4h 17m
5. Chirality3h 39m
6. Thermodynamics and Kinetics1h 22m
7. Substitution Reactions1h 48m
8. Elimination Reactions2h 30m
9. Alkenes and Alkynes2h 9m
10. Addition Reactions3h 19m
11. Radical Reactions1h 58m
12. Alcohols, Ethers, Epoxides and Thiols2h 42m
13. Alcohols and Carbonyl Compounds2h 17m
14. Synthetic Techniques1h 26m
15. Analytical Techniques:IR, NMR, Mass Spect7h 3m
16. Conjugated Systems6h 13m
17. Ultraviolet Spectroscopy51m
18. Aromaticity2h 34m
19. Reactions of Aromatics: EAS and Beyond5h 1m
20. Phenols55m
21. Aldehydes and Ketones: Nucleophilic Addition4h 56m
22. Carboxylic Acid Derivatives: NAS2h 51m
23. The Chemistry of Thioesters, Phophate Ester and Phosphate Anhydrides1h 10m
24. Enolate Chemistry: Reactions at the Alpha-Carbon1h 53m
25. Condensation Chemistry2h 9m
26. Amines1h 43m
27. Heterocycles2h 0m
28. Carbohydrates5h 53m
29. Amino Acids4h 20m
30. Peptides and Proteins2h 42m
31. Catalysis in Organic Reactions1h 30m
32. Lipids 2h 50m
33. The Organic Chemistry of Metabolic Pathways2h 52m
34. Nucleic Acids1h 32m
35. Transition Metals6h 14m
36. Synthetic Polymers1h 49m

1. A Review of General Chemistry

Condensed Structural Formula

Organic Chemistry

1. A Review of General Chemistry

Condensed Structural Formula

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5:53 minutes

Problem 13c,d

Textbook Question

Draw line-angle structures for the compounds (a) through (h).
c. CH₃CH₂COCN
d. CH₂CHCHO

Verified step by step guidance

Step 1: Understand the line-angle structure representation. In organic chemistry, line-angle structures are a simplified way to depict molecules. Each vertex represents a carbon atom, and lines represent bonds between atoms. Hydrogen atoms attached to carbons are usually not shown explicitly.

Step 2: For compound (c) CH3CH2COCN, identify the functional groups. This compound contains an ethyl group (CH3CH2-), a carbonyl group (C=O), and a nitrile group (-CN).

Step 3: Draw the line-angle structure for compound (c). Start with the ethyl group, which is represented by two connected lines. Then, connect the carbonyl group to the ethyl group, followed by the nitrile group. Ensure the correct connectivity: CH3CH2-CO-CN.

Step 4: For compound (d) CH2CHCHO, identify the functional groups. This compound contains an alkene group (CH2=CH-) and an aldehyde group (-CHO).

Step 5: Draw the line-angle structure for compound (d). Begin with the alkene group, represented by two lines with a double bond between them. Then, connect the aldehyde group to the alkene group. Ensure the correct connectivity: CH2=CH-CHO.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Line-Angle Structures

Line-angle structures, also known as skeletal formulas, are a simplified representation of organic molecules. They use lines to represent chemical bonds and vertices or ends of lines to represent carbon atoms, omitting hydrogen atoms bonded to carbons for clarity. This method helps visualize complex molecules efficiently.

Functional Groups

Functional groups are specific groups of atoms within molecules that are responsible for the characteristic chemical reactions of those molecules. In the given compounds, recognizing functional groups like nitriles (CN) and aldehydes (CHO) is crucial for drawing accurate line-angle structures and understanding their reactivity.

Carbon Chain Identification

Identifying the carbon chain is essential for constructing line-angle structures. It involves determining the sequence of carbon atoms in a molecule, which forms the backbone of the structure. For example, CH3CH2COCN has a three-carbon chain, while CH2CHCHO has a three-carbon chain with an aldehyde group at the end.

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