Table of contents

1. A Review of General Chemistry5h 5m
2. Molecular Representations1h 14m
3. Acids and Bases2h 46m
4. Alkanes and Cycloalkanes4h 17m
5. Chirality3h 39m
6. Thermodynamics and Kinetics1h 22m
7. Substitution Reactions1h 48m
8. Elimination Reactions2h 30m
9. Alkenes and Alkynes2h 9m
10. Addition Reactions3h 19m
11. Radical Reactions1h 58m
12. Alcohols, Ethers, Epoxides and Thiols2h 42m
13. Alcohols and Carbonyl Compounds2h 17m
14. Synthetic Techniques1h 26m
15. Analytical Techniques:IR, NMR, Mass Spect7h 3m
16. Conjugated Systems6h 13m
17. Ultraviolet Spectroscopy51m
18. Aromaticity2h 34m
19. Reactions of Aromatics: EAS and Beyond5h 1m
20. Phenols55m
21. Aldehydes and Ketones: Nucleophilic Addition4h 56m
22. Carboxylic Acid Derivatives: NAS2h 51m
23. The Chemistry of Thioesters, Phophate Ester and Phosphate Anhydrides1h 10m
24. Enolate Chemistry: Reactions at the Alpha-Carbon1h 53m
25. Condensation Chemistry2h 9m
26. Amines1h 43m
27. Heterocycles2h 0m
28. Carbohydrates5h 53m
29. Amino Acids4h 20m
30. Peptides and Proteins2h 42m
31. Catalysis in Organic Reactions1h 30m
32. Lipids 2h 50m
33. The Organic Chemistry of Metabolic Pathways2h 52m
34. Nucleic Acids1h 32m
35. Transition Metals6h 14m
36. Synthetic Polymers1h 49m

4. Alkanes and Cycloalkanes

Cis vs Trans

Organic Chemistry

4. Alkanes and Cycloalkanes

Cis vs Trans

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3:27 minutes

Problem 13c

Textbook Question

Given the name, draw the structure of the following alkenes.
(c) (Z)-3-isopropylhept-3-ene

Verified step by step guidance

Step 1: Break down the name of the compound systematically. The name '(Z)-3-isopropylhept-3-ene' indicates that the compound is an alkene with a double bond at position 3 of a heptane chain (7 carbon atoms in the main chain). The '(Z)' configuration specifies that the higher-priority groups on either side of the double bond are on the same side.

Step 2: Draw the parent chain, which is heptane (a straight chain of 7 carbon atoms). Number the chain from left to right to ensure the double bond is at the lowest possible position. The double bond is located between carbons 3 and 4.

Step 3: Add the substituent. The name specifies a 3-isopropyl group, meaning an isopropyl group (-CH(CH3)2) is attached to carbon 3 of the main chain. Place this group on the appropriate carbon.

Step 4: Assign the (Z) configuration. To do this, identify the priority of the groups attached to the double-bonded carbons (C3 and C4) based on the Cahn-Ingold-Prelog priority rules. Ensure that the higher-priority groups on both carbons are on the same side of the double bond.

Step 5: Finalize the structure by double-checking the placement of the double bond, substituents, and the (Z) configuration. Ensure the structure matches the IUPAC name '(Z)-3-isopropylhept-3-ene'.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Alkene Structure

Alkenes are hydrocarbons that contain at least one carbon-carbon double bond (C=C). The presence of this double bond affects the geometry and reactivity of the molecule. In the case of (Z)-3-isopropylhept-3-ene, the 'hept' indicates a seven-carbon chain, and the double bond is located between the third and fourth carbons.

Stereochemistry

Stereochemistry refers to the spatial arrangement of atoms in molecules and how this affects their chemical behavior. The designation '(Z)' indicates that the highest priority substituents on either side of the double bond are on the same side, leading to a specific geometric isomer. Understanding stereochemistry is crucial for accurately drawing and interpreting the structure of alkenes.

Substituents and Branching

Substituents are groups of atoms attached to the main carbon chain, which can influence the physical and chemical properties of the molecule. In (Z)-3-isopropylhept-3-ene, the 'isopropyl' group is a branched substituent at the third carbon of the heptane chain. Recognizing how to identify and place these substituents is essential for constructing the correct molecular structure.

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