Name the following carboxylic acids (when possible, give both ...

Question

Name the following carboxylic acids (when possible, give both a common name and a systematic name).

(a)

(b)

(c)

Accepted Answer

Hey everyone and welcome back. And today we're going to provide a suitable name for each of the following structures. Give both a systematic name and the common name. If possible, starting with the first structure, we have to understand that we have a code book silic acid group, which corresponds to the highest priority in terms of functional groups. And therefore, this is an asset. We want to count the number of carbon atoms in our parents. So that'd be 12345. So let's label them. That's 12345. And essentially whenever you have five that corresponds to pencil, Novick acid. Keep in mind that the subjects that we're using for asset is, oh I see, right. Pantano Wake acid. That's why we use the suffix because we have a curb oxalic acid. And now the world last thing we want to do here is just find our substitution. So at position number two, we have our bromo substitution. We have that moment over here. So we're going to say to bromo. And at position number three, we have our metal group, we have our C three, we are ready to give it a name, right? We start with our suspicions arranged alphabetically. So in terms of alphabetical priority, bromo goes first followed by method. So the name for this one would be two bromo, Then we have three muscles. And as we said, this is penso nitric acid. So we're going to finish our name with an actual asset here. So Pensa nitric acid, now this is our systematic name because we named it according to the IU back rules. So we can say that this one is systematic and we simply want to think about the common name. Now, whenever you're dealing with a common name, you want to, first of all make sure that you understand how to name the acid itself. So instead of using pencil quick asset, we are going to think about what is the common name for a five member carbon chain where we have our curb oxalic acid, right? So if we have our five member chain over here, that would correspond to valid Eric acid, let's keep that in mind. So we have the Lyric acid, right? Such as let's say formic acid or acetic acid, you know these and you know that for example, formic acid has one carbon atom. Acetic acid has to in case of pencil malic acid, we call it a lyric acid is a common name. So this is something that we have to know and we simply want to identify our substitutions. Now we recall that the very first carbon adjacent to our car book silic acid carbon or basic position. Number two is called the alpha position. The next one is called the beta position. The next one is called gamma position and so on. So we have substitutions that alpha and beta position. So we can say that at alpha position, we have our bromo substitution and at beta position, we have our metal group. So it's very similar to what we did before. But now, instead of pentatonic, we're using the lyric acid instead of actual numbers, we're using alpha and beta to indicate our positions of substitutions with respect to carve oxalic acid group. So now we're going to give it a name just as we did before, we are going to arrange our substitutions alphabetically and we're going to say that BROMO goes first. So that'd be Alfa bromo. Now we have beta missile and now we know that this is the Lyric acid well done. So that will be our common name, let's label it. And let's say that this is the common name. Okay. So we have our answers. We are ready to move on to the second structure. Once again, notice how we have our asset and the structure. So that would correspond to an asset because assets essentially correspond to the highest possible priority, right? So this would be an asset. We simply want to find the longest chain. So if we start with carbon number one, for our acidic carbon over here or basically the the carbon atom within the curb oxalic acid group. So that's number one, number two, number three, number four, number 56 and seven, right? So first of all, we can say that this would be happy to know we casted because we have seven carbon atoms. Let's label that, that would be helpful to know like acid because we have seven carbon atoms in our chain or based on the parenting the longest chain. So now that this is our helps in a weak acid, but there are several more things to consider. Let's start with our suspicions positions three and four, right? Three and four, we have two method groups because we have two of them. We're going to use a prefix diet to indicate the multiplicity of metal. We don't have any other substations. But it's really important to understand that at position three, we have our double bond. So we can also say that we will have an M which corresponds to a double bond when whenever we are dealing with a double bond as though it was an actual suspicion and not the main functional group in our compound because this is not really an al keen, this is a carb oxalic acid that has a double bond we're going to use in to represent that double bond at position three. And this is not yet everything we have to consider our stereo comes through. Remember that whenever we have Elkins, we can have E or C di asti M R s. And if you look at carbon number three, between the two, you have a longer chain just above the double bond. So this is your priority number one, this is your priority number two. Essentially you have C three vs siege to see, right? So essentially because you have a difference in hydrogen versus carbon, this gets a higher priority. So we don't even need to worry about the other atoms. However, just sufficient to understand that this chain is longer, in addition to that, it has oxygen's, so that's priority number one. And if we look at the adjacent carbon atom, again, we have a metal versus a longer L kill chain. So the longer L kill chain will get the first priority or based on the higher priority. Now, the highest priority groups are on the same side of the double bonds, we call it our C di astronomer. So now we know everything about it, right? We know that, that see, we know the substations, we know which assets were dealing with. So we are going to give it a name. Let's remember that. First of all, we're going to start with the configurations were going to say easy. Okay, because whenever you have any sort of stereo is um are you definitely want to start with parentheses at E or C R or S whichever that is right. So we have C we have to identify our suspicions. There were only two. So we're going to say three, comma four and we identify the multiplicity that we die metal because we have two of them. And out here, it's really important to remember that we will already give it a name and we will say this is helped, economic asset. But let's start by writing, helped and just the fact that there is this double bond, we're going to add hyphen and we are going to say at position number three, we have our in which says at position number three, you just have your double bond, it basically starts at position three. So have three in and now we are ready, right? We have everything. So we can just say we are ready to add our suffix OIC and now we are just going to add acid because we have a code book silic acid. So we have C three comma four die method helped three Inuit assets. So we're just going to label this is our final answer for the name of this acid. The common name for this structure will not be analyzed. Because if you think about it, if you, if this is your carbon number one, then you have your position at the beta position, you have a metal supposition and a double bond. And then at your gamma position, you have an additional metal group, right? So the name a common, it would be too complicated especially due to the fact that if you look at position three, it has a double bond. And because it has a double bond, not only single substitue in essentially, the common name becomes too complex. So we will not have any common name there, there will be only our systematic name. Now, moving on to the final ones, the 3rd 1, we once again identified that there is our curb oxalic acid group, right? And you may recall that whenever you have your benzene ring with a curb oxalic acid group bonded, said this is called Benzali Cassidy, right? Because you have your benzene ring, you're turning it into an asset, it becomes benzo weak acid. So we have our benzoate acid fragment that only has two substations. That said that's how simple the problem becomes. So we have to understand that the curb oxalic acid has always monitor the first carbon atom with within the ring. And now we want to go clockwise because this will allow us to minimize the coefficients for each booming. We have two substations. So we understand that at position two and three, we we have two BROMO substitutes and that's it. So the name for this one would be 23, right? Because we have two equivalent substitute prints dye bromo because we have two of them benzoate acid and that's it. So let's give it a name. So for number three, once again, our analysis becomes with starts with understanding that this has been so weak asset. We understand that positions two and 3, they have Romo substitutions and there are two. So we're going to use the eye and that's it. So the name for this one would be two comma three Dye Bromo because there are two bromo substitutions. And now we are giving our asset its name so that we've been so weak acid, let's label this is our systematic name. And similarly to the previously solves problem, we are not going to think about the common name because if you look at the structure, it's just too complicated once again, right? You have your benzo weak acid and when you go along your ring, it has double bonds. It it's not really possible to say that there is some sort of alfa beta position. You're actually having a benzene ring, right? Whenever you want to use a common name, you just want to have a linear chain with submissions monitored with no double bonds, no rings, right? This will essentially simplify everything. But if you're still Cassidy is bonded to a benzene ring, you will not worry about the common name. So we got all of our names for number one, number two and number three, we said that the common name was only given for pencil gnomic acid. In part number one, the systematic name was two bromo three method, Pencil OIC acid. The common name was alpha bromo, beta metal balearic acid for number two, we had Z three comma four, the metal Hep three in OIC acid, right? Because we had our Elkin and Z configuration. No common name, death was just a systematic name. And for number three, we had our 23 D bromo Ben's OIC acid. Once again, no common name based on our answers. We may conclude that the correct answer to the multiple choice question is D and thank you for watching.

Name the following carboxylic acids (when possible, give both a common name and a systematic name).
(a)
(b)
(c)

Key Concepts

Carboxylic Acids

Nomenclature of Organic Compounds

Substituents and Their Effects on Naming

Watch next