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Multiple Choice
Predict the splitting pattern (multiplicity) for the following molecule:
A
A=singlet; B=doublet; C=singlet
B
A=singlet; B=singlet; C=doublet
C
A=doublet; B=singlet; C=doublet
D
A=singlet; B=singlet; C=singlet
Verified step by step guidance
1
Identify the hydrogen environments in the molecule. In the given structure, there are three distinct groups labeled A, B, and C.
Consider the group labeled A. It is a methyl group (CH₃) attached to a quaternary carbon, which means it has no neighboring hydrogens to couple with. Therefore, the splitting pattern for A is a singlet.
Examine the group labeled B. This is a methylene group (CH₂) adjacent to a carbonyl group (C=O). The carbonyl group does not have any hydrogens, and the adjacent quaternary carbon also lacks hydrogens. Thus, B will also appear as a singlet.
Look at the group labeled C. It is another methyl group (CH₃) attached to a carbonyl group. Similar to A, there are no neighboring hydrogens to cause splitting, so C will appear as a singlet.
Summarize the splitting patterns: A=singlet, B=singlet, C=singlet. This is consistent with the correct answer provided.