Predict the splitting pattern (multiplicity) for the following molecule:
15. Analytical Techniques:IR, NMR, Mass Spect
1H NMR:Spin-Splitting (N + 1) Rule
- Multiple Choice
- Multiple Choice
Predict the splitting pattern (multiplicity) for the following molecule:
- Textbook Question
Predict the multiplicity (the number of peaks as a result of splitting) and the chemical shift for each shaded proton in the following compounds.
(a)
(b)
- Textbook Question
Why is there no coupling between the a and c protons or between the b and c protons in the cis and trans alkenes shown in Figure 14.20?
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- Textbook Question
Predict the splitting patterns for the signals given by the compounds in Problem 4.
d.
- Textbook Question
Predict the splitting patterns for the signals given by the compounds in Problem 4.
c. CH2=CCl2
- Textbook Question
Label each set of chemically equivalent protons, using a for the set that will be at the lowest frequency in the 1H NMR spectrum, b for the next lowest, and so on. Indicate the multiplicity of each signal.
c.
- Textbook Question
In Figure 15.34, Ha was assumed to be 'up.' How does the analysis change if we assume instead that Ha is down?
- Textbook Question
Though Figure 15.34 was concerned with the appearance of Ha, how would Hb appear in the spectrum?
- Textbook Question
Every number in Pascal’s triangle is the sum of the two numbers above it. Given this, fill in the missing numbers.
- Textbook Question
Indicate the number of signals and the multiplicity of each signal in the 1H NMR spectrum of each of the following compounds:
c. ClCH2CH2CH2Cl
- Textbook Question
Indicate the number of signals and the multiplicity of each signal in the 1H NMR spectrum of each of the following compounds:
a. CH3CH2CH2CH2CH2CH3
- Textbook Question
Predict the splitting patterns for the signals given by the compounds in Problem 4.
i.
- Textbook Question
Predict the splitting patterns for the signals given by the compounds in Problem 4.
j.
- Textbook Question
Draw all of the possible spin states to explain why a hydrogen with four neighbors appears as a quintet (quint, five peaks).