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Multiple Choice
Provide the IUPAC name for the following compound.
A
2-bromo-3-hydroxy-4-hexen-6-oic acid
B
5-bromo-2-hexen-1,4-diol
C
6-bromo-3-hexen-1,4-diol
D
5-bromo-4-hydroxy-2-hexenoic acid
Verified step by step guidance
1
Identify the longest carbon chain that contains the highest priority functional group, which in this case is the carboxylic acid group (-COOH). The chain has six carbon atoms, making it a hexanoic acid derivative.
Number the carbon chain starting from the carboxylic acid group to give it the lowest possible number. This makes the carboxylic acid carbon number 1.
Identify and number the substituents on the carbon chain. The bromine (Br) is on carbon 5, and the hydroxyl group (OH) is on carbon 4. There is also a double bond between carbons 2 and 3.
Combine the substituents and the main chain name. The substituents are listed in alphabetical order: 5-bromo and 4-hydroxy. The double bond is indicated by the suffix '-en' and its position is specified as 2-hexenoic acid.
Assemble the full IUPAC name by combining the substituents, the position of the double bond, and the main chain name: 5-bromo-4-hydroxy-2-hexenoic acid.