Table of contents

1. A Review of General Chemistry5h 5m
2. Molecular Representations1h 14m
3. Acids and Bases2h 46m
4. Alkanes and Cycloalkanes4h 17m
5. Chirality3h 39m
6. Thermodynamics and Kinetics1h 22m
7. Substitution Reactions1h 48m
8. Elimination Reactions2h 30m
9. Alkenes and Alkynes2h 9m
10. Addition Reactions3h 19m
11. Radical Reactions1h 58m
12. Alcohols, Ethers, Epoxides and Thiols2h 42m
13. Alcohols and Carbonyl Compounds2h 17m
14. Synthetic Techniques1h 26m
15. Analytical Techniques:IR, NMR, Mass Spect7h 3m
16. Conjugated Systems6h 13m
17. Ultraviolet Spectroscopy51m
18. Aromaticity2h 34m
19. Reactions of Aromatics: EAS and Beyond5h 1m
20. Phenols55m
21. Aldehydes and Ketones: Nucleophilic Addition4h 56m
22. Carboxylic Acid Derivatives: NAS2h 51m
23. The Chemistry of Thioesters, Phophate Ester and Phosphate Anhydrides1h 10m
24. Enolate Chemistry: Reactions at the Alpha-Carbon1h 53m
25. Condensation Chemistry2h 9m
26. Amines1h 43m
27. Heterocycles2h 0m
28. Carbohydrates5h 53m
29. Amino Acids4h 20m
30. Peptides and Proteins2h 42m
31. Catalysis in Organic Reactions1h 30m
32. Lipids 2h 50m
33. The Organic Chemistry of Metabolic Pathways2h 52m
34. Nucleic Acids1h 32m
35. Transition Metals6h 14m
36. Synthetic Polymers1h 49m

2. Molecular Representations

Functional Groups

Organic Chemistry

2. Molecular Representations

Functional Groups

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4:28 minutes

Problem 25d,e

Textbook Question

Draw a Lewis structure, and classify each of the following compounds. The possible classifications are as follows: alcohol ether ketone aldehyde carboxylic acid alkene
(d) CH₃CH₂OCHCH₂
(e)

Verified step by step guidance

Step 1: Begin by identifying the molecular formula for the compound CH3CH2OCHCH2. This compound consists of carbon (C), hydrogen (H), and oxygen (O) atoms.

Step 2: Draw the Lewis structure for the compound. Start by arranging the carbon atoms in a chain, as they typically form the backbone of organic molecules. Connect the carbon atoms with single bonds.

Step 3: Add the oxygen atom to the structure. In this compound, the oxygen atom is bonded to two carbon atoms, forming an ether linkage. Place the oxygen between the two carbon chains.

Step 4: Complete the Lewis structure by adding hydrogen atoms to satisfy the valency of each carbon atom. Each carbon atom should have four bonds, either with other carbon atoms, hydrogen atoms, or the oxygen atom.

Step 5: Classify the compound based on its functional group. The presence of an oxygen atom bonded to two carbon atoms indicates that this compound is an ether. Therefore, classify CH3CH2OCHCH2 as an ether.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Lewis Structure

A Lewis structure is a diagram that represents the valence electrons of atoms within a molecule. It shows how electrons are shared between atoms, indicating bonds and lone pairs. Understanding Lewis structures is crucial for visualizing molecular geometry and predicting reactivity.

Functional Groups

Functional groups are specific groups of atoms within molecules that are responsible for the characteristic chemical reactions of those molecules. Identifying functional groups such as alcohols, ethers, ketones, aldehydes, carboxylic acids, and alkenes is essential for classifying organic compounds and predicting their behavior.

Molecular Classification

Molecular classification involves categorizing compounds based on their functional groups and structural features. This classification helps in understanding the properties and reactivity of compounds. For example, ethers contain an oxygen atom bonded to two alkyl groups, while alkenes have carbon-carbon double bonds.