Table of contents

1. A Review of General Chemistry5h 5m
2. Molecular Representations1h 14m
3. Acids and Bases2h 46m
4. Alkanes and Cycloalkanes4h 17m
5. Chirality3h 39m
6. Thermodynamics and Kinetics1h 22m
7. Substitution Reactions1h 48m
8. Elimination Reactions2h 30m
9. Alkenes and Alkynes2h 9m
10. Addition Reactions3h 19m
11. Radical Reactions1h 58m
12. Alcohols, Ethers, Epoxides and Thiols2h 42m
13. Alcohols and Carbonyl Compounds2h 17m
14. Synthetic Techniques1h 26m
15. Analytical Techniques:IR, NMR, Mass Spect7h 3m
16. Conjugated Systems6h 13m
17. Ultraviolet Spectroscopy51m
18. Aromaticity2h 34m
19. Reactions of Aromatics: EAS and Beyond5h 1m
20. Phenols55m
21. Aldehydes and Ketones: Nucleophilic Addition4h 56m
22. Carboxylic Acid Derivatives: NAS2h 51m
23. The Chemistry of Thioesters, Phophate Ester and Phosphate Anhydrides1h 10m
24. Enolate Chemistry: Reactions at the Alpha-Carbon1h 53m
25. Condensation Chemistry2h 9m
26. Amines1h 43m
27. Heterocycles2h 0m
28. Carbohydrates5h 53m
29. Amino Acids4h 20m
30. Peptides and Proteins2h 42m
31. Catalysis in Organic Reactions1h 30m
32. Lipids 2h 50m
33. The Organic Chemistry of Metabolic Pathways2h 52m
34. Nucleic Acids1h 32m
35. Transition Metals6h 14m
36. Synthetic Polymers1h 49m

28. Carbohydrates

Monosaccharide

Organic Chemistry

28. Carbohydrates

Monosaccharide

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Multiple Choice

Which of the following differences could be found among molecules of the same monosaccharide?

Different types of glycosidic bonds

Different stereoisomers

Different molecular formulas

Different functional groups

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Verified step by step guidance

Understand the concept of monosaccharides: Monosaccharides are the simplest form of carbohydrates and consist of a single sugar molecule. They are the building blocks for more complex carbohydrates.

Recognize the concept of stereoisomers: Stereoisomers are molecules that have the same molecular formula and sequence of bonded atoms (constitution), but differ in the three-dimensional orientations of their atoms in space.

Identify why different stereoisomers can exist for the same monosaccharide: Monosaccharides can have different stereoisomers due to the presence of chiral centers, which are carbon atoms bonded to four different groups. The arrangement of these groups can vary, leading to different stereoisomers.

Clarify why glycosidic bonds, molecular formulas, and functional groups are not relevant differences for the same monosaccharide: Glycosidic bonds are relevant in polysaccharides, not monosaccharides. The molecular formula and functional groups are consistent within a specific monosaccharide.

Conclude that the correct difference among molecules of the same monosaccharide is the presence of different stereoisomers, due to variations in the spatial arrangement of atoms around chiral centers.