What is each compound's systematic name?
i.

Question

What is each compound's systematic name?

i. Chemical structure of a cycloalkane with a bromine atom attached, labeled

j. Chemical structure of cyclohexanol, a six-membered carbon ring with a hydroxyl (OH) group attached.

Accepted Answer

Welcome back everyone. What is the appropriate systematic name of each compound? The first structure is an alkyl bromide. And the second structure is an alcohol. We're going to start our analysis with the first structure. And our first step is to identify the parent whenever we have several side chains bonded to a ring or a ring that is greater in the number of carbon atoms than any of the side chains than our parent is the ring itself. So in this case, we have a five membered ring which is cyclopse. We have to think about our substitutions and actually, we have two substitutions. We have our bromo substituent in our metal group. We have to recall that alky ha lights do not prioritize halogens. In other words, our parent will be an al cane and the bromo substituent will just be a substituent, it will not have an effect on the name. So our next step is to identify our substitutions, we have B R substitute, which is a bromo group and ach three substituent which is a muscle group. The next step is to enumerate our ring properly so that we can add the coefficients or locus for our substitutions. And actually, we always want to minimize the coefficient of our substitutions. So we have two options. We can assign carbon number one to the carbon atom that is bonded to bromine. And carbon number two that is bonded to the methyl group or go counterclockwise. And then assign the fir the first carbon atom to the one that is bonded to the methyl group. And the second one that is bonded to the BROMO group, in each case, we have the minimal possible coefficients. So that means whenever this is the case, we want to take into account the alphabetical priorities because bromo group gets the alphabetical priority, we want to make sure that it also gets the first carbon, the metal group alphabetically doesn't get the priority. So it's OK to assign carbon number two to it. So for the enumeration step, we understand that we enumerate our ring clockwise, starting with the first carbon atom that responded to the BROMO group well done. And now that we have enumerated our parent, we understand that carbon number one has a bromo substituent and carbon number two has a methyl scient. So that is all of the information that we need. Now, we're going to arrange our substitutions alphabetically and name the structure. So we end up with one bromo, right? The alphabetical priority has been taken into account and now the other substi that we have is two methyl and now we some play finish our name using the parent which is Cyclopse well done. So that will be our first name one bromo, two methyl cycle pense for the first structure moving on to the second one. We first will understand that the second structure is significantly different. It has an alcohol group and an alcohol group will be prioritized in this case, meaning it will automatically define carbon number one. So our parents will be slightly different. Previously, we said that it was a psycho alkin. Now it will be a cyclic alcohol and we can say that the parent in this case. Yes, Cyclo pencil because once again, we have a five member ring. So let's go ahead and stay that, that ol because carbon number one has an alcohol group just as a rule, we don't need to state, we don't need to state Cyclo pen one. Oh Since it, it is already clear to us that the alcohol group is always bonded to carbon number one. So moving on to our substitutions, we understand that there is only one actual substituent present and it gets carba number two because that is the only way for us to minimize the locus by going clockwise from carbon. Number one, that has an alcohol group, we can get carbon number two that contains the metal group, we cannot go counter clockwise because unfortunately, that will give us a much greater coefficient or low count. So we can say that for the substitutions we only have our C three group, which is the methyl group. And for the third step, as we said, we are going to enumerate it, enumerate our rank specifically clockwise. And now we are ready to give it a name. Carbon number two has a metal group and that's our one and only substituent because the age group is taken into account within the parent name, meaning we are some saying two methyl. And because we are done with our substitutions, we simply finish our name by adding Cyp pencil and that will be our final answer. The first structure is a one bromo, two methyl cyclopse and the second structure is two methyl cyclo pencil. Thank you for watching and I hope to see you in the next video.

What is each compound's systematic name?
i.
j.

Key Concepts

Nomenclature of Organic Compounds

Functional Groups

Cycloalkanes

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