Join thousands of students who trust us to help them ace their exams!Watch the first video
Multiple Choice
Beginning from 1-pentyne, synthesize the following compound via a catalytic allylic alkylation reaction.
A
B
C
D
Verified step by step guidance
1
Start with 1-pentyne, which is an alkyne with five carbon atoms. The first step involves the partial reduction of the alkyne to a trans-alkene using sodium in liquid ammonia (Na/NH₃). This is known as the Birch reduction.
Next, perform a radical bromination using bromine (Br₂) and light (hv). This step introduces a bromine atom at the allylic position of the newly formed alkene, creating an allylic bromide.
Now, use palladium tetrakis(triphenylphosphine) (Pd(PPh₃)₄) as a catalyst to facilitate the allylic alkylation reaction. This involves the substitution of the bromine atom with a nucleophile, which in this case is the enolate ion derived from the diketone shown in the image.
The enolate ion is generated from the diketone, which has two carbonyl groups. The enolate formation involves the deprotonation of the alpha hydrogen between the two carbonyl groups, creating a resonance-stabilized anion.
Finally, the enolate ion attacks the allylic bromide, resulting in the formation of the desired compound with the new carbon-carbon bond. The stereochemistry of the product is determined by the configuration of the starting materials and the reaction conditions.