Join thousands of students who trust us to help them ace their exams!Watch the first video
Multiple Choice
Determine the monomer created from the reaction between toluene diisocyanate and ethylene diol.
A
B
C
D
Verified step by step guidance
1
Identify the functional groups in the reactants: Toluene diisocyanate contains two isocyanate groups (\( \text{NCO} \)), and ethylene diol contains two hydroxyl groups (\( \text{OH} \)).
Understand the reaction mechanism: The isocyanate group reacts with the hydroxyl group to form a urethane linkage. This involves the nucleophilic attack of the hydroxyl oxygen on the carbon of the isocyanate group, forming a carbamate (urethane) linkage.
Visualize the structure of the monomer: The reaction between one isocyanate group and one hydroxyl group forms a urethane linkage, \( \text{NHCOO} \). Since both reactants are di-functional, the reaction will form a linear monomer with urethane linkages at both ends.
Consider the repeating unit: The monomer formed will have a structure where the urethane linkage connects the aromatic ring of toluene diisocyanate to the ethylene chain of ethylene diol.
Analyze the images: The images provided show structures with urethane linkages, indicating the formation of a monomer with the expected urethane linkage between the aromatic ring and the ethylene chain.