Predict which member of each pair will be more acidic. Explain your answers. c. 2-chloroethanol or 2,2-dichloroethanol
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Identify the functional group in both compounds. Both 2-chloroethanol and 2,2-dichloroethanol contain a hydroxyl (-OH) group, making them alcohols. The acidity of alcohols is influenced by the stability of the conjugate base formed after deprotonation.
Analyze the substituents attached to the carbon chain. In 2-chloroethanol, there is one chlorine atom attached to the carbon adjacent to the hydroxyl group. In 2,2-dichloroethanol, there are two chlorine atoms attached to the same carbon adjacent to the hydroxyl group.
Consider the inductive effect of chlorine atoms. Chlorine is an electronegative atom, and its presence withdraws electron density through the sigma bond (inductive effect). This stabilizes the conjugate base (alkoxide ion) by delocalizing the negative charge.
Compare the extent of the inductive effect in both compounds. In 2,2-dichloroethanol, the presence of two chlorine atoms exerts a stronger inductive effect compared to the single chlorine atom in 2-chloroethanol. This makes the conjugate base of 2,2-dichloroethanol more stable.
Conclude that 2,2-dichloroethanol is more acidic than 2-chloroethanol because the stronger inductive effect from the two chlorine atoms leads to greater stabilization of the conjugate base, making it easier for the hydroxyl group to lose a proton.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Acidity and pKa
Acidity in organic chemistry refers to the tendency of a compound to donate a proton (H+). The strength of an acid is often measured by its pKa value; lower pKa values indicate stronger acids. Understanding the relationship between structure and acidity is crucial for predicting which compound in a pair will be more acidic.
The inductive effect describes how the presence of electronegative atoms or groups can stabilize or destabilize a negative charge in a molecule. In the context of acidity, electron-withdrawing groups, such as chlorine, can increase acidity by stabilizing the conjugate base formed after deprotonation. This effect is particularly relevant when comparing compounds with different substituents.
When comparing the acidity of two compounds, it is essential to analyze the nature and position of substituents. In this case, 2-chloroethanol has one chlorine atom, while 2,2-dichloroethanol has two. The additional chlorine in the latter compound enhances the inductive effect, leading to greater stabilization of the conjugate base and thus increased acidity.