Draw the structures and give the common and systematic names f...

Question

Draw the structures and give the common and systematic names for the seven alkynes with molecular formula C₆H₁₀.

Accepted Answer

Hey, everyone. And welcome back, determine the structures along with the pack names of all possible al kinds that have the molecular formula C five H eight. The first step for us is to verify if this formula works for us. And if it defines an al kind, recall that al kinds correspond to the molecular formula of C N H two and minus two. And if you substitute and equals five, then you get two and minus two gives you 10 minus two, that's indeed eight. So this is an al Qaeda, meaning there is one triple bond and some al kill group bonded to it. As long as it is a terminal al kinds, we have two possible al kinds, a terminal alkaline and an internal al kind where, where you don't have any hydrants here. Instead, you have to al killed groups on each end of your triple bond. Okay. So that would be an internal one. And based on these two types of al kinds, we will determine all of the possible structures. Let's start with terminal ones. So we're going to draw our triple bond. And then we essentially want to think about how many more carbon atoms do we need to add? Let's not worry about counting the number of hydrogen atoms because the molecular formula satisfies an alkaline. This means as long as we have one triple bond, we will have the right number of hydrogen atoms that will always be eight. So if we have two carbon atoms, we need to add three more. So let's add them, we have to, then we are going to get the third one, the fourth one and the fifth one, right. So five carbon atoms. Now, is there any other possibility to get a terminal alkaline, we can draw a triple bond. And the only way for us to get another terminal al kind is to branch our propose substitution recall that we can branch it because it has three carbon atoms, the minimum, the minimum number of carbon atoms that we can create a branch chain off. So essentially we're going to take that metal substitution and we're going to add it here to get an isopropyl substitution. So that be essentially our first carbon atom. And then we will have two methods responded to it. So we have branched our propel substitute it into an isopropyl group because there is no more branching possible. We are done with our terminal al kinds and we are just going to think about our possible internal al kinds. So if we try triple bond, we are going to choose our shortest possible change so that the method group on one end. And we have a total of three carbon atoms, meaning we need two more. So we're going to add an ethyl substitution on the other end. And that would be it, we cannot branch any of these two groups. So we are done with our analysis and we understand that we have three structures now that we got three structures, we want to name them and recall that al kinds will be named using a suffix Ein starting with the first one because there are five carbon atoms in the parent, we are giving it a name tent, right? Because there are five carbon atoms in the parent, then we need to add a dash to present at which position we have our triple bond. So because it starts at position number one, we're going to add one and then we're going to add under dash and use our suffix right? To indicate that this is an Al Kind, Maybe Plant one Line. That means there are five carbon atoms in our parents. One eye means that there's a triple bond starting at position one. Now moving on to the next one, our longest chain or our parent chain has 1234 carbon atoms, right? So that would be our b time. But in addition to that, if you enumerate your parents, that would be 1234, you may also notice that at position three have your metal group. The reason why we're going from here is because we always want to make sure that we're minimizing the number for the position of our triple bond. So that's why we go from here as carbon number one will represent our triple bond or basically our triple bonded carbon to be more accurate. So we have beat sign in that position. Number three, we have our metal group. So we can say that this structure will be called three methods. We indicate the position of our substitution, right? And then because it's beat sign, we are going to say beauty, then we are going to indicate the position of the triple bond, which is position one. And then we're going to add our suffix sign. So there will be three method butte 19 position number three has a metal group, the parent corresponds to four carbon atoms and the triple bond starts at carbon number one. And finally, for the last one, we are going to identify our parents. That would be 12345 carbon atoms, right? So we have another pen sign, but the triple bond doesn't start at position number one. Instead it starts at position number two. So we're going to say pants to sign. So that's the main difference. If you look at the structure number one and number three is that they're both bands sign structures. But the triple bond starts at carbon number one and here starts at carbon number two. That's why its planned to ein for clarity, you can enumerate your chains 12345. So it starts at position number one and here 12345, it starts at position number two. So we got all of our possible structures, we can label them as our final answer. So these three would correspond to our three possible al kinds that correspond to the molecular formula of C five H eight. And based on our answer, we can conclude that the correct answer to the multiple choice question is A B Thank you for watching.

Draw the structures and give the common and systematic names for the seven alkynes with molecular formula C₆H₁₀.

Key Concepts

Alkynes

Nomenclature of Organic Compounds

Structural Isomerism

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Draw the structures and give the common and systematic names for the seven alkynes with molecular formula C6H10.

Key Concepts

Alkynes

Nomenclature of Organic Compounds

Structural Isomerism

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Draw the structures and give the common and systematic names for the seven alkynes with molecular formula C₆H₁₀.