Table of contents

1. A Review of General Chemistry5h 5m
2. Molecular Representations1h 14m
3. Acids and Bases2h 46m
4. Alkanes and Cycloalkanes4h 17m
5. Chirality3h 39m
6. Thermodynamics and Kinetics1h 22m
7. Substitution Reactions1h 48m
8. Elimination Reactions2h 30m
9. Alkenes and Alkynes2h 9m
10. Addition Reactions3h 19m
11. Radical Reactions1h 58m
12. Alcohols, Ethers, Epoxides and Thiols2h 42m
13. Alcohols and Carbonyl Compounds2h 17m
14. Synthetic Techniques1h 26m
15. Analytical Techniques:IR, NMR, Mass Spect7h 3m
16. Conjugated Systems6h 13m
17. Ultraviolet Spectroscopy51m
18. Aromaticity2h 34m
19. Reactions of Aromatics: EAS and Beyond5h 1m
20. Phenols55m
21. Aldehydes and Ketones: Nucleophilic Addition4h 56m
22. Carboxylic Acid Derivatives: NAS2h 51m
23. The Chemistry of Thioesters, Phophate Ester and Phosphate Anhydrides1h 10m
24. Enolate Chemistry: Reactions at the Alpha-Carbon1h 53m
25. Condensation Chemistry2h 9m
26. Amines1h 43m
27. Heterocycles2h 0m
28. Carbohydrates5h 53m
29. Amino Acids4h 20m
30. Peptides and Proteins2h 42m
31. Catalysis in Organic Reactions1h 30m
32. Lipids 2h 50m
33. The Organic Chemistry of Metabolic Pathways2h 52m
34. Nucleic Acids1h 32m
35. Transition Metals6h 14m
36. Synthetic Polymers1h 49m

21. Aldehydes and Ketones: Nucleophilic Addition

Naming Ketones

Organic Chemistry

21. Aldehydes and Ketones: Nucleophilic Addition

Naming Ketones

Previous problemNext problem

4:10 minutes

Problem 56d

Textbook Question

The following molecules were named incorrectly according to IUPAC nomenclature. Give the correct name of these compounds.
d. (E)-2-methylhex-2-en-6-al

Verified step by step guidance

Step 1: Identify the longest carbon chain that contains the highest priority functional group. In this case, the aldehyde group (-CHO) is the highest priority, and the longest chain containing it is a six-carbon chain.

Step 2: Number the carbon chain starting from the end nearest to the highest priority functional group, which is the aldehyde group. This means the aldehyde group should be at position 1.

Step 3: Identify and name any substituents on the main chain. Here, there is a methyl group attached to the second carbon.

Step 4: Determine the correct position and configuration of the double bond. The double bond is between carbon 2 and carbon 3, and it is in the E configuration, meaning the highest priority groups on each carbon are on opposite sides.

Step 5: Combine all the elements to form the correct IUPAC name. The name should reflect the position of the double bond, the configuration, the substituents, and the aldehyde group.

Verified video answer for a similar problem:

This video solution was recommended by our tutors as helpful for the problem above

Video duration:

Play a video:

Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

IUPAC Nomenclature

IUPAC nomenclature is a standardized system for naming chemical compounds. It ensures that each compound has a unique and universally accepted name, based on its structure. Key elements include identifying the longest carbon chain, functional groups, and the position of substituents, ensuring clarity and consistency in chemical communication.

E/Z Isomerism

E/Z isomerism is a type of stereoisomerism found in alkenes, where the spatial arrangement of substituents around the double bond differs. 'E' (entgegen) indicates that the highest priority groups are on opposite sides, while 'Z' (zusammen) means they are on the same side. This is determined using the Cahn-Ingold-Prelog priority rules, crucial for accurate naming and understanding molecular geometry.

Functional Groups in Aldehydes

Aldehydes are organic compounds characterized by the presence of a carbonyl group (C=O) bonded to a hydrogen atom. In nomenclature, the aldehyde group is typically given priority in numbering, and the suffix '-al' is used. Understanding the placement and naming of aldehyde groups is essential for correctly identifying and naming compounds with this functional group.

Watch next

Master Nomenclature with a bite sized video explanation from Johnny

Start learning