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Multiple Choice
Using 3-methyl-1-butene as a starting material, predict the final product based on the list of reagents given?
A
B
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D
Verified step by step guidance
1
Begin with the starting material, 3-methyl-1-butene, which is an alkene. The first reagent, HBr in the presence of a peroxide (ROOR), will add across the double bond via a radical mechanism.
In the presence of peroxides, HBr adds to the alkene in an anti-Markovnikov fashion. This means the bromine atom will attach to the less substituted carbon of the double bond, resulting in 1-bromo-3-methylbutane.
Next, the reaction with NaI will involve a nucleophilic substitution. Iodide (I-) is a good nucleophile and will replace the bromine atom in 1-bromo-3-methylbutane, forming 1-iodo-3-methylbutane.
The final step involves the use of KOEt, which is potassium ethoxide. This reagent can act as a base to perform an elimination reaction, specifically an E2 elimination, to form an alkene.
The E2 elimination will result in the formation of an alkene, and the ethoxide ion (EtO-) can also act as a nucleophile to perform a nucleophilic substitution, leading to the formation of an ether. The final product will be an ether with the ethoxy group (OEt) attached to the carbon chain.