Based on the curved arrow formalism given, predict the products of this acid/base reaction. <img src="https://media.pearsoncmg.com/ph/esm/ecs_mullins_organic1e/msa/content/practice-test/img/Ch04_Q04_QT.jpg" alt="The figure illustrates a reversible reaction. The reaction contains two reactants. The first reactant has the following structure: A 2-carbon alkane chain is depicted as a line structure using 1 line. C 2 is single bonded to N on the upper right. N is single bonded to H on the lower right. The N atom has 2 lone pairs of electrons and carries a negative charge. The second reactant has the following structure: A 2-carbon alkane chain is depicted as a line structure using 1 line. C 1 is single bonded to O on the lower left. O is single bonded to H on the upper left. The O atom has 2 lone pairs of electrons. A curved arrow from a lone pair of electrons on N points to H in the second reactant. A second curved arrow from the single bond between H and O in the second reactant points to O." />

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1. A Review of General Chemistry5h 5m
2. Molecular Representations1h 14m
3. Acids and Bases2h 46m
4. Alkanes and Cycloalkanes4h 17m
5. Chirality3h 39m
6. Thermodynamics and Kinetics1h 22m
7. Substitution Reactions1h 48m
8. Elimination Reactions2h 30m
9. Alkenes and Alkynes2h 9m
10. Addition Reactions3h 19m
11. Radical Reactions1h 58m
12. Alcohols, Ethers, Epoxides and Thiols2h 42m
13. Alcohols and Carbonyl Compounds2h 17m
14. Synthetic Techniques1h 26m
15. Analytical Techniques:IR, NMR, Mass Spect7h 3m
16. Conjugated Systems6h 13m
17. Ultraviolet Spectroscopy51m
18. Aromaticity2h 34m
19. Reactions of Aromatics: EAS and Beyond5h 1m
20. Phenols55m
21. Aldehydes and Ketones: Nucleophilic Addition4h 56m
22. Carboxylic Acid Derivatives: NAS2h 51m
23. The Chemistry of Thioesters, Phophate Ester and Phosphate Anhydrides1h 10m
24. Enolate Chemistry: Reactions at the Alpha-Carbon1h 53m
25. Condensation Chemistry2h 9m
26. Amines1h 43m
27. Heterocycles2h 0m
28. Carbohydrates5h 53m
29. Amino Acids4h 20m
30. Peptides and Proteins2h 42m
31. Catalysis in Organic Reactions1h 30m
32. Lipids 2h 50m
33. The Organic Chemistry of Metabolic Pathways2h 52m
34. Nucleic Acids1h 32m
35. Transition Metals6h 14m
36. Synthetic Polymers1h 49m

3. Acids and Bases

Acids and Bases

Organic Chemistry

3. Acids and Bases

Acids and Bases

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Multiple Choice

Based on the curved arrow formalism given, predict the products of this acid/base reaction.

The figure illustrates the structures of two products. The first product has the following structure: A 2-carbon alkane chain is depicted as a line structure using 1 line. C 2 is single bonded to N on the upper right. The N atom has 1 lone pair of electrons and is single bonded to H above and H on the lower right. The second product has the following structure: A 2-carbon alkane chain is depicted as a line structure using 1 line. C 1 is single bonded to O on the lower left. O has three lone pairs of electrons and carries a negative charge.

The figure illustrates the structure of a molecule. A 1 N, 1 O, and 4 C heteronuclear alkane chain is depicted as a line structure using 5 zigzag lines. N occupies the third position, and O occupies the fourth position. N has 1 lone pair of electrons and is single bonded to H above. O has 2 lone pairs of electrons.

The figure illustrates the structure of an ion. N, single bond, H, single bond, O. H carries a negative charge. N has 1 lone pair of electrons and is single bonded to H above. N is single bonded on the lower left to C 2 of a 2-carbon alkane chain depicted as a line structure using 1 line. O has 2 lone pairs of electrons and is single on the upper right to C 1 of a second 2-carbon alkane chain depicted as a line structure using 1 line.

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Verified step by step guidance

Identify the reactants: The first image shows an amine (ethylamine) and an alcohol (ethanol) with curved arrows indicating electron movement.

Analyze the curved arrows: The arrow from the nitrogen atom of the amine to the hydrogen atom of the alcohol indicates that the nitrogen is donating a pair of electrons to form a bond with the hydrogen.

Consider the acid-base reaction: The amine acts as a base, accepting a proton (H+) from the alcohol, which acts as an acid.

Predict the products: The proton transfer results in the formation of an ammonium ion (protonated amine) and an alkoxide ion (deprotonated alcohol).

Draw the products: The ammonium ion will have a positive charge on the nitrogen, and the alkoxide ion will have a negative charge on the oxygen, as shown in the second image.