Draw the substitution products for each of the following SN2 reactions. If the products can exist as stereoisomers, show which stereoisomers are formed: a. (3S,4S)-3-bromo-4-methylhexane + CH3O- b. (3S,4R)-3-bromo-4-methylhexane + CH3O-
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Step 1: Identify the type of substitution reaction taking place. Since CH3O- is a strong nucleophile and base, the reaction is likely to proceed via an SN2 mechanism, which involves a single-step nucleophilic substitution. SN2 reactions are stereospecific and result in inversion of configuration at the carbon undergoing substitution.
Step 2: Analyze the structure of the starting material. For part (a), the compound is (3S, 4S)-3-bromo-4-methylhexane. The bromine atom is attached to the 3rd carbon, which is a stereocenter. The methyl group is attached to the 4th carbon, which is also a stereocenter. For part (b), the compound is (3S, 4R)-3-bromo-4-methylhexane, with similar structural features but differing stereochemistry at the 4th carbon.
Step 3: Determine the stereochemical outcome of the substitution. In an SN2 reaction, the nucleophile (CH3O-) attacks the carbon bonded to the leaving group (Br) from the opposite side, leading to inversion of configuration at the 3rd carbon. For part (a), the 3rd carbon changes from S to R configuration. For part (b), the 3rd carbon also changes from S to R configuration.
Step 4: Consider the stereochemistry of the 4th carbon. Since the substitution occurs only at the 3rd carbon, the stereochemistry of the 4th carbon remains unchanged. For part (a), the 4th carbon retains its S configuration. For part (b), the 4th carbon retains its R configuration.
Step 5: Draw the products. For part (a), the product is (3R, 4S)-3-methoxy-4-methylhexane. For part (b), the product is (3R, 4R)-3-methoxy-4-methylhexane. Ensure that the stereochemistry is clearly indicated in the drawings, showing the inversion at the 3rd carbon and the unchanged configuration at the 4th carbon.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Nucleophilic Substitution Reactions
Nucleophilic substitution reactions involve the replacement of a leaving group in a molecule by a nucleophile. In this context, the nucleophile is CH3O-, which attacks the carbon atom bonded to the bromine in the bromoalkane. Understanding the mechanism (either SN1 or SN2) is crucial, as it influences the stereochemistry of the products formed.
Nucleophiles and Electrophiles can react in Substitution Reactions.
Stereochemistry and Stereoisomers
Stereochemistry refers to the spatial arrangement of atoms in molecules and how this affects their chemical behavior. Stereoisomers are compounds that have the same molecular formula and connectivity but differ in the orientation of their atoms in space. In the given reactions, the stereochemistry of the starting materials will determine the types of stereoisomers produced, which may include enantiomers and diastereomers.
Chirality is a property of a molecule that makes it non-superimposable on its mirror image, often due to the presence of a chiral center (a carbon atom bonded to four different groups). Molecules that are chiral can exist as two enantiomers, which rotate plane-polarized light in opposite directions. Recognizing chirality in the reactants is essential for predicting the stereoisomeric products of the reactions.