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Multiple Choice
Provide the structure of the product formed from the reaction of 1-bromo-2,4,6- trinitrobenzene with one equivalent of sodium methoxide.
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Identify the reactants: 1-bromo-2,4,6-trinitrobenzene and sodium methoxide (NaOCH3). The structure of 1-bromo-2,4,6-trinitrobenzene includes a benzene ring with a bromine atom and three nitro groups (NO2) at the 2, 4, and 6 positions.
Understand the reaction type: This is a nucleophilic aromatic substitution (S_NAr) reaction. The presence of electron-withdrawing nitro groups on the benzene ring makes it susceptible to nucleophilic attack.
Determine the nucleophile: Sodium methoxide (NaOCH3) dissociates in solution to form methoxide ion (OCH3^-), which acts as the nucleophile.
Predict the site of nucleophilic attack: The methoxide ion will attack the carbon atom bonded to the bromine atom, as the bromine is a good leaving group and the adjacent nitro groups stabilize the negative charge through resonance.
Outline the reaction mechanism: The methoxide ion attacks the carbon atom bonded to the bromine, displacing the bromine and forming a new carbon-oxygen bond. The product is 2,4,6-trinitroanisole, where the methoxy group (OCH3) replaces the bromine atom on the benzene ring.