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Multiple Choice
What is the Kw of pure water at 20.0°C, if the pH is 7.083?
A
8.26 × 10-8
B
6.82 × 10-15
C
7.23 × 10-14
D
1.00 × 10-14
Verified step by step guidance
1
Understand that Kw is the ion product of water, which is the product of the concentrations of hydrogen ions [H⁺] and hydroxide ions [OH⁻] in water: Kw = [H⁺][OH⁻].
Recognize that the pH of a solution is related to the concentration of hydrogen ions by the formula: pH = -log[H⁺].
Use the given pH value of 7.083 to find the concentration of hydrogen ions [H⁺] by rearranging the pH formula: [H⁺] = 10^(-pH).
Since pure water is neutral, the concentration of hydroxide ions [OH⁻] is equal to the concentration of hydrogen ions [H⁺]. Therefore, [OH⁻] = [H⁺].
Calculate Kw by multiplying the concentrations of [H⁺] and [OH⁻] obtained from the previous steps: Kw = [H⁺] × [OH⁻].