Multiple Choice
Draw the Lewis Dot Structure for the following ion:PCl4+.
4. Molecular Compounds
Lewis Dot Structures: Ions (Simplified)
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Determine the Lewis Dot Structure for the following ion:SCl42+.
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Verified step by step guidance1
Identify the central atom in the ion. In SCl4^2+, sulfur (S) is the central atom because it is less electronegative than chlorine (Cl) and can form multiple bonds.
Determine the total number of valence electrons available. Sulfur has 6 valence electrons, and each chlorine has 7 valence electrons. The ion has a 2+ charge, meaning 2 electrons are removed from the total count.
Calculate the total number of valence electrons: 6 (from S) + 4*7 (from Cl) - 2 (due to the 2+ charge) = 34 valence electrons.
Arrange the electrons to form bonds. Place a single bond between the sulfur and each chlorine atom, using 8 electrons (2 per bond).
Distribute the remaining electrons to satisfy the octet rule for each chlorine atom. Each chlorine should have 6 more electrons to complete its octet, using up the remaining 26 electrons.
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