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Multiple Choice
Determine the Lewis Dot Structure for the following ion:O22–.
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Verified step by step guidance
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Identify the total number of valence electrons for the O2^2- ion. Each oxygen atom has 6 valence electrons, and the 2- charge indicates an additional 2 electrons, giving a total of 14 valence electrons.
Arrange the two oxygen atoms side by side and initially place a single bond between them. This single bond accounts for 2 electrons, leaving 12 electrons to be distributed.
Distribute the remaining 12 electrons to satisfy the octet rule for each oxygen atom. Start by placing 6 electrons (3 pairs) around each oxygen atom.
Check if each oxygen atom has a complete octet. If not, consider forming double or triple bonds by converting lone pairs into bonding pairs.
Verify the formal charge on each oxygen atom. The goal is to have the formal charges as close to zero as possible, while ensuring the overall charge of the ion is -2.