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Multiple Choice
Which of these molecules exhibit the most number of different intermolecular forces?
A
B
C
Verified step by step guidance
1
Identify the types of intermolecular forces: The main types of intermolecular forces are London dispersion forces, dipole-dipole interactions, and hydrogen bonding.
Analyze the first molecule (propane): Propane (C3H8) is a nonpolar molecule, so it primarily exhibits London dispersion forces.
Analyze the second molecule (formaldehyde): Formaldehyde (CH2O) is a polar molecule due to the difference in electronegativity between carbon, hydrogen, and oxygen, and the presence of a carbonyl group (C=O). It exhibits dipole-dipole interactions and London dispersion forces.
Consider hydrogen bonding: Hydrogen bonding occurs in molecules where hydrogen is directly bonded to highly electronegative atoms like nitrogen, oxygen, or fluorine. Formaldehyde does not have hydrogen bonding because the hydrogen atoms are not bonded to the oxygen atom.
Compare the molecules: Propane only exhibits London dispersion forces, while formaldehyde exhibits both London dispersion forces and dipole-dipole interactions. Therefore, formaldehyde exhibits a greater variety of intermolecular forces.