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Multiple Choice
Determine if the compound of BCl2F is polar or nonpolar.
A
polar
B
nonpolar
Verified step by step guidance
1
Identify the central atom in the compound BCl2F. In this case, it is Boron (B).
Determine the molecular geometry of the compound. BCl2F has three substituents (two Cl atoms and one F atom) around the central Boron atom, which suggests a trigonal planar geometry.
Consider the electronegativity of the atoms involved. Fluorine (F) is more electronegative than Chlorine (Cl), which means the B-F bond will have a greater dipole moment than the B-Cl bonds.
Assess the symmetry of the molecule. In a trigonal planar geometry, if all substituents were the same, the molecule would be nonpolar. However, since F is more electronegative than Cl, the dipoles do not cancel out completely.
Conclude that due to the difference in electronegativity and the resulting dipole moments, the molecule BCl2F is polar.