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Multiple Choice
Calculate mass (grams) needed for the following base equivalent:0.18 mEq of Mg(OH)2.
A
5.3×10–3 g
B
0.010 g
C
10 g
D
5.3 g
Verified step by step guidance
1
Understand that the problem is asking for the mass of Mg(OH)_2 needed to provide 0.18 milliequivalents (mEq) of base.
Recall that the equivalent weight of a compound is the molecular weight divided by the number of equivalents per mole. For Mg(OH)_2, which provides 2 hydroxide ions (OH^-), the number of equivalents is 2.
Calculate the molar mass of Mg(OH)_2 by adding the atomic masses: Mg (24.31 g/mol), O (16.00 g/mol), and H (1.01 g/mol). The formula is Mg(OH)_2, so the molar mass is 24.31 + 2(16.00 + 1.01).
Determine the equivalent weight of Mg(OH)_2 by dividing its molar mass by the number of equivalents (2).
Use the formula: mass (g) = (mEq × equivalent weight) / 1000 to find the mass in grams needed for 0.18 mEq of Mg(OH)_2.