Write an equation for the acid-base equilibrium of:

...

Question

Write an equation for the acid-base equilibrium of:

a.Pyrrolidine and water

Label each species in the equilibrium as either an acid or a base.

Accepted Answer

All right. Hi, everyone. So this question is asking us, what is the equilibrium equation or the acid base reaction of Pip pyridine and water label each species as a base or acid. So first, I want to go ahead and start off here by writing out our reactants. In this case, Pyridine and water recall. It. Piperidine is a six member ring in which there are five carbons and one nitrogen atom inside of the ring. So nitrogen, in this case is inside of the six memberm ring and nitrogen. If you recall has a lone pair of electrons as well, N one hydrogen, and then we have water which is course age two. So to discuss which of these species is an acid and which one is the base? Let's talk about the bronte lowery a acid based definition briefly in the Bronzy Lari acid based definition recall that acids are species that can donate a proton. So they themselves lose a proton and bass therefore, can accept the proton donated by the bronzed acid. Now, in this case, if I consider the structure of Pip Pyridine, notice how Pip Pyridine has a low pair of electrons on nitrogen. This means that nitrogen can accept a proton using those electrons, meaning that it is a base. And that makes sense considering that amines are generally basis and neutral amines are generally weak basis. Now, water, if you recall is very interesting, right? Because it is actually amphoteric water can behave as either a proton donor or an acceptor because not only does it have protons in the structure of water, oxygen also has lone pairs of electrons. But in this case, right, because we established that piperidine is a base, water is going to behave like an acid in this specific reaction. So now we can talk about the products, right? Because piperidine is my base, the first product I'm going to draw is the result of the nitrogen accepting an extra proton. So I would draw nitrogen with two protons attached as opposed to one in the beginning. So that would be NH two instead of NH in the beginning. So recall that an acid based e uh reaction, excuse me, is going to affect the charge of the resulting species as well because recall there for every proton accepted or gained, the charge is going to increase by one. So in this case, we go from a neutral charge or zero charge in piperidine to a positive one charge in the piper deum ion. And so now the piper deum ion is considered to be the conjugate acid of the base. And the reason for this is because now it is capable of donating a proton to become neutral once more. So now let's talk about the conjugate base of the acid, which is the species that results from our acid here losing a proton. So in this case, I would go ahead and draw water with one less proton. But once again, recall the effect that this has on the chart of the species great losing a proton will decrease the charge by one. So we go from a zero charge on water to a charge of negative one in the conjugate base, which specifically is hydroxide. Now, the reason we say that this is the conjugate base of the acid is because now hydroxide can accept a proton to become neutral once more. So with this in mind right here is our final answer. And we can see that as a result of this acid base reaction, we can come up with two acid base pairs because our base in a bronzy Lowry acid base reaction is proton to yield its conjugate acid. Whereas the acid is detonated, they yield its conjugate base. And with that being said, here is your final answer. So with that being said, if you stuck around to the end of this video, thank you so very much for watching. And I hope you found this helpful

Struggling with GOB Chemistry?

Write an equation for the acid-base equilibrium of:

a.Pyrrolidine and water

Label each species in the equilibrium as either an acid or a base.

Watch next

Amine Reactions practice set

Struggling with GOB Chemistry?

Write an equation for the acid-base equilibrium of:a.Pyrrolidine and waterLabel each species in the equilibrium as either an acid or a base.

Watch next

Amine Reactions practice set

Write an equation for the acid-base equilibrium of:

a.Pyrrolidine and water

Label each species in the equilibrium as either an acid or a base.