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1. Matter and Measurements4h 31m
2. Atoms and the Periodic Table5h 23m
3. Ionic Compounds2h 18m
4. Molecular Compounds2h 18m
5. Classification & Balancing of Chemical Reactions3h 17m
6. Chemical Reactions & Quantities2h 27m
7. Energy, Rate and Equilibrium3h 46m
8. Gases, Liquids and Solids3h 25m
9. Solutions4h 10m
10. Acids and Bases3h 29m
11. Nuclear Chemistry56m
BONUS: Lab Techniques and Procedures1h 38m
BONUS: Mathematical Operations and Functions47m
12. Introduction to Organic Chemistry1h 34m
13. Alkenes, Alkynes, and Aromatic Compounds2h 12m
14. Compounds with Oxygen or Sulfur1h 6m
15. Aldehydes and Ketones1h 1m
16. Carboxylic Acids and Their Derivatives1h 11m
17. Amines39m
18. Amino Acids and Proteins1h 51m
19. Enzymes1h 37m
20. Carbohydrates1h 41m
21. The Generation of Biochemical Energy2h 8m
22. Carbohydrate Metabolism2h 22m
23. Lipids2h 26m
24. Lipid Metabolism1h 45m
25. Protein and Amino Acid Metabolism1h 37m
26. Nucleic Acids and Protein Synthesis2h 54m

21. The Generation of Biochemical Energy

Electron Transport Chain

GOB Chemistry

21. The Generation of Biochemical Energy

Electron Transport Chain

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Multiple Choice

FADH₂ can be oxidized at both complex I and II in the inner membrane of mitochondria. (T/F)

True

False

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Verified step by step guidance

Understand the role of FADH2 in cellular respiration: FADH2 is a reduced coenzyme that donates electrons to the electron transport chain (ETC) in mitochondria.

Identify the complexes involved in the electron transport chain: The ETC consists of four main complexes (I, II, III, and IV) located in the inner mitochondrial membrane.

Determine where FADH2 enters the electron transport chain: FADH2 donates electrons specifically to Complex II (succinate dehydrogenase), not Complex I.

Clarify the function of Complex I: Complex I (NADH: ubiquinone oxidoreductase) is where NADH donates its electrons, not FADH2.

Conclude the statement's accuracy: Since FADH2 is oxidized at Complex II and not at Complex I, the statement that FADH2 can be oxidized at both Complex I and II is false.