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Multiple Choice
Draw a Lewis Dot Structure that obeys the octet rule for the following compound:NH2OH.
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Verified step by step guidance
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Identify the total number of valence electrons in NH2OH. Nitrogen (N) has 5 valence electrons, each hydrogen (H) has 1 valence electron, and oxygen (O) has 6 valence electrons. Therefore, the total is 5 (N) + 2*1 (H) + 6 (O) + 1 (H) = 14 valence electrons.
Determine the central atom. In NH2OH, nitrogen (N) is typically the central atom because it is less electronegative than oxygen (O) and can form multiple bonds.
Arrange the atoms around the central nitrogen atom. Connect the nitrogen to two hydrogens and one oxygen. The oxygen is then connected to the remaining hydrogen.
Distribute the remaining valence electrons to satisfy the octet rule. Start by placing lone pairs on the oxygen atom to complete its octet, then place any remaining electrons on the nitrogen atom.
Ensure that all atoms (except hydrogen, which follows the duet rule) have a complete octet. Adjust the placement of electrons if necessary to ensure that the nitrogen and oxygen atoms each have 8 electrons around them.