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Multiple Choice
A carbon–oxygen double bond within a sugar molecule absorbs electromagnetic radiation at a frequency of 6.0 x 1012 s-1. What portion of the electromagnetic spectrum does this represent?
A
Radio Waves
B
Micowave
C
Infrared
D
Green Light
E
Gamma Ray
Verified step by step guidance
1
Identify the given frequency of the electromagnetic radiation, which is \(6.0 \times 10^{12} \text{ s}^{-1}\).
Recall the ranges of frequencies for different portions of the electromagnetic spectrum. For example, infrared radiation typically falls within the range of \(10^{12} \text{ s}^{-1}\) to \(10^{14} \text{ s}^{-1}\).
Compare the given frequency \(6.0 \times 10^{12} \text{ s}^{-1}\) with the known frequency ranges for each portion of the electromagnetic spectrum.
Determine which range the given frequency falls into. Since \(6.0 \times 10^{12} \text{ s}^{-1}\) is within the range for infrared radiation, it indicates that the carbon–oxygen double bond absorbs in the infrared portion of the spectrum.
Conclude that the portion of the electromagnetic spectrum represented by the given frequency is infrared.