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Multiple Choice
Predict the amide product formed when 2,2-dimethylpropanoic acid reacts with dimethylamine.
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Verified step by step guidance
1
Identify the reactants: 2,2-dimethylpropanoic acid and dimethylamine.
Recognize that the reaction between a carboxylic acid and an amine typically forms an amide through a condensation reaction, releasing water.
Draw the structure of 2,2-dimethylpropanoic acid, which has a central carbon atom bonded to two methyl groups and a carboxylic acid group (COOH).
Draw the structure of dimethylamine, which consists of a nitrogen atom bonded to two methyl groups and a hydrogen atom.
Combine the structures by forming a bond between the carbonyl carbon of the acid and the nitrogen of the amine, replacing the OH group of the acid with the nitrogen, and releasing a molecule of water (H2O).