Determine the percent composition of air in the lungs from the fo...

Question

Determine the percent composition of air in the lungs from the following composition in partial pressures: PN2 = 573 mmHg, PO2 = 100 mmHg, PCO2 = 40 mmHg, and PH2O = 47 mmHg; all at 37 °C and 1 atm pressure.

Accepted Answer

Welcome back everyone. What are the percent composition of each gas and a vessel at 34 Celsius and a 1.50 80 m pressure. If the vessel contains the following pressures where for helium, we have a pressure of 655 millimeters of mercury. For Xenon, we have a pressure of 194 millimeters of mercury. For Argon, we have a pressure of 120 millimeters of mercury. And for Krypton, we have a pressure of 171 millimeters of mercury. Let's begin by recalling how to calculate percent composition in which we should recall. This is found from taking the pressure of our gas divided by the total pressure of our gaseous mixture Within the vessel. This quotient is then multiplied by 100%. Now, in order to find our total pressure within our vessel, we're going to take the some of the pressures given for each of our gasses. And so we have 655 mm of mercury added to millimeters of mercury as the pressure of helium plus the pressure of xenon gas. Then we have plus our pressure of Argon 120 millimeters of mercury and then plus our pressure of Krypton given as 171 millimeters of mercury from the prompt. So taking the sum, we would find our total pressure is equal to a value of 1140 of mercury within our vessel. So now let's go ahead and calculate our percent composition. First of our first gas helium, Wherein we take the pressure of our helium gas in the numerator as 655 mm of mercury. And in our denominator, we plug in our total pressure Of gasses in our vessel as 1140 of Mercury. And then multiplying this by 100 will find that our percent composition of helium is equal to 57.5%. This would be our first answer as our percent composition of helium gas. And now moving on to our next gas, we want to find our percent composition of xenon gas. So following the same process, where in the numerator, we plug in our pressure of xenon, given as 194 millimeters of mercury Divided by our total pressure of 1140 of mercury. And then multiplying by 100%,, We find our percent composition of xenon gas equal to 17.0%. This would be our second answer. So far as our percent composition of Xenon. And let's just make more room because we have two more gasses to calculate for. So moving on to finding our percent composition of argon gas we're going to take in our numerator are pressure of argon gas given in the prompt as 120 millimeters of mercury divided by the total pressure in our vessel of gasses being 1140 mm of mercury and then multiplying this quotient by 100%,, We find our partial pressure of argon gas equal to or sorry, our percent composition of argon gas equal to a value of 10.5%. So this is our third answer as our percent composition of argon gas. And lastly, we have our percent composition of Krypton gas to calculate for where in our numerator we plug in our pressure of Krypton given as millimeters of mercury. And in our denominator, we have our total pressure of gasses in our vessel as millimeters of mercury. And then again, multiplying this quotient by 100%,, we find our pressure or sorry percent composition of Krypton gas Equal to exactly 15.0%. And this would be our fourth final answer. So all of our answers highlighted in yellow represent our percent compositions of our gasses of helium xenon argon and krypton, all corresponding to choice D in the multiple choice as the final answer. So I hope that this made sense and let us know if you have any questions.

Struggling with GOB Chemistry?

Determine the percent composition of air in the lungs from the following composition in partial pressures: PN2 = 573 mmHg, PO2 = 100 mmHg, PCO2 = 40 mmHg, and PH2O = 47 mmHg; all at 37 °C and 1 atm pressure.

Watch next

Dalton's Law: Partial Pressure (Simplified) practice set