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Multiple Choice
How many carbon atoms are lost when one glucose molecule undergoes glycolysis?
A
0
B
2
C
1
D
3
Verified step by step guidance
1
Understand the process of glycolysis: Glycolysis is the metabolic pathway that converts glucose (C6H12O6) into pyruvate, releasing energy and producing ATP. It occurs in the cytoplasm of cells.
Identify the structure of glucose: Glucose is a six-carbon sugar, represented by the chemical formula C6H12O6.
Examine the products of glycolysis: During glycolysis, one molecule of glucose is converted into two molecules of pyruvate. Each pyruvate molecule contains three carbon atoms.
Calculate the total number of carbon atoms in the products: Since two pyruvate molecules are produced, the total number of carbon atoms in the products is 2 x 3 = 6 carbon atoms.
Compare the number of carbon atoms in glucose and pyruvate: Since the initial glucose molecule has 6 carbon atoms and the final products (two pyruvate molecules) also have a total of 6 carbon atoms, no carbon atoms are lost during glycolysis.