A 5.12 L sample of solution contains 0.230 g of potassium sulfate, K 2 SO 4 . Determine the concentration of K 2 SO 4 in ppm if the density of the solution is 1.30 g/mL.

A 5.12 liter sample of a solution contains 0.230 grams of potassium sulfate, k two s o four. Determine the concentration of potassium sulfate in parts per million, if the density of the solution is 1.30 grams per milliliter. Alright. So they're giving to us the grams of our solute. That tells me that parts per million here will be grams of solute divided by grams of solution times 10 to the 6. So we already have the grams of our solute, our potassium sulfate. So plug that in. And what we need to do now is figure out our grams of solution. So to figure out our grams of solution, realize they're giving us the density of the solution and the volume of the solution. So I'm gonna take 5.12 liters. Remember 1 milli is 10 to the negative 3. Now that I have the milliliters of solution, I can multiply it by its density, and that'll give me the grams of my solution. So when I do that I'm gonna get 5,100 oh, actually no. I'm gonna get 6,000, 6,656 grams of solution. So here, that is our grams of solution times 10 to the 6, since this is parts per million. That gives me 34.6 PPM as my final answer, which is option a.

Table of contents

Skip topic navigation

1. Matter and Measurements4h 31m
2. Atoms and the Periodic Table5h 23m
3. Ionic Compounds2h 18m
4. Molecular Compounds2h 18m
5. Classification & Balancing of Chemical Reactions3h 17m
6. Chemical Reactions & Quantities2h 27m
7. Energy, Rate and Equilibrium3h 46m
8. Gases, Liquids and Solids3h 25m
9. Solutions4h 10m
10. Acids and Bases3h 29m
11. Nuclear Chemistry56m
BONUS: Lab Techniques and Procedures1h 38m
BONUS: Mathematical Operations and Functions47m
12. Introduction to Organic Chemistry1h 34m
13. Alkenes, Alkynes, and Aromatic Compounds2h 12m
14. Compounds with Oxygen or Sulfur1h 6m
15. Aldehydes and Ketones1h 1m
16. Carboxylic Acids and Their Derivatives1h 11m
17. Amines39m
18. Amino Acids and Proteins1h 51m
19. Enzymes1h 37m
20. Carbohydrates1h 41m
21. The Generation of Biochemical Energy2h 8m
22. Carbohydrate Metabolism2h 22m
23. Lipids2h 26m
24. Lipid Metabolism1h 45m
25. Protein and Amino Acid Metabolism1h 37m
26. Nucleic Acids and Protein Synthesis2h 54m

9. Solutions

Parts per Million (ppm)

GOB Chemistry

9. Solutions

Parts per Million (ppm)

Previous problemNext problem

Struggling with GOB Chemistry?

Join thousands of students who trust us to help them ace their exams!Watch the first video

Multiple Choice

A 5.12 L sample of solution contains 0.230 g of potassium sulfate, K₂SO₄. Determine the concentration of K₂SO₄ in ppm if the density of the solution is 1.30 g/mL.

34.6 ppm

28.9 ppm

22.3 ppm

43.6 ppm

Previous problemNext problem

Verified step by step guidance

First, calculate the mass of the solution using its volume and density. The volume is given as 5.12 L, which is equivalent to 5120 mL. Use the formula: \( \text{mass of solution} = \text{volume} \times \text{density} \).

Next, determine the mass of potassium sulfate (K2SO4) in the solution, which is already provided as 0.230 g.

To find the concentration in parts per million (ppm), use the formula: \( \text{ppm} = \left( \frac{\text{mass of solute}}{\text{mass of solution}} \right) \times 10^6 \).

Substitute the mass of K2SO4 and the mass of the solution into the ppm formula. Remember that ppm is a unit that expresses the ratio of the mass of the solute to the mass of the solution, multiplied by one million.

Finally, perform the calculation to determine the concentration of K2SO4 in ppm. Compare your result with the given options to identify the correct answer.