Complete and balance the equation for each of the following react...

Question

Complete and balance the equation for each of the following reactions:b. Ca(s) + H₂SO₄(aq) →

Accepted Answer

Welcome back, everyone. We need to give the complete balanced chemical reaction for the following equation where we're given half of our equation with solid barium reacting with sulfuric acid. We're going to begin by categorizing our two reagents. Beginning with Beri. We want to recognize that it is a group two, a metal on the periodic table, which is why we're given the solid label from our prompt for Beli and then our second reactant sulfuric acid we want to recall is one of our memorized strong acids from our textbooks and consists of two ion protons given by the subscript of two next to hydrogen. Meaning that this is a Dipro acid or dibasic acid because we have these two available protons that are able to be donated and will undergo dissociation. Next, we have within this formula for sulfuric acid. Our sulfate poly atomic an ion which we recall is S 042 minus. Now, our first atom Perri is going to be considered as we stated a medal which reacts with our second compound, which we would label as covalent because we have our nonmetal hydrogen bonded to our poly atomic ion sulfate. So we have a metal reacting with a will say acid, covalent acid. And as a result, we want to recall that for this type of reaction, we have a single replacement reaction in which our first product would be hydrogen gas. And our second product would be a salt not to form our chemical formula. For our salt, we would have the combination of our metal plus our anion from our acid. So in this case, our reaction would appear as follows where we have solid beri reacting with sulfuric acid to form on our po side hydrogen gas. And then our salts would be our metal beli bonded to our sulfate anion S 04 recall that beri forms a plus two count on being a group two A element and sulfate forms a minus two anion. So those charges will neutralize and we will not have a net charge for beli sulfate. We have a net charge of zero. So next, we want to recall our solubility rules for sulfates in which we would recall that because we have a beryllium sulfate, this is soluble and therefore we give it the label aqueous. Now, we need to ensure that we have a balanced equation. So comparing our atoms on our reactant side, beri, hydrogen sulfur and then oxygen to the atoms on our product side, barium hydrogen sulfur and oxygen. Beginning with our reactant side, we have one atom of beri given by the subscript of two in hydrogen or sorry. In sulfuric acid, we have a total of two hydrogens. Then in our formula for sulfuric acid, we can count one sulfur and given by the subscript of four in sulfuric acid. We have four oxygens. On our product side, we can count a total of one atom of beri. Given by the subscript of two in hydrogen gas. We have two atoms of hydrogen in barium sulfate. We have one atom of sulfur and given by its subscript of four, we have four atoms of oxygen. So we can confirm that our equation as written forms our balanced equation. And our final answer is going to be that one mole of soli beri reacts with one mole of sulfuric acid to form one mole of hydrogen gas and one mole of beli sulfate. This entire balanced equation is our final answer. I hope this made sense and let us know if you have any questions.

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Complete and balance the equation for each of the following reactions:b. Ca(s) + H₂SO₄(aq) →

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