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Multiple Choice
Identify the least stable covalent bond.
A
N–C
B
F–Na
C
N=C
D
N≡C
E
all same strength
Verified step by step guidance
1
Understand that covalent bonds involve the sharing of electron pairs between atoms. The stability of a covalent bond is influenced by factors such as bond order, electronegativity differences, and atomic size.
Examine the bond types given: N–C, F–Na, N=C, N≡C. Note that F–Na is not a covalent bond; it is an ionic bond due to the large electronegativity difference between fluorine and sodium.
Consider bond order: Single bonds (e.g., N–C) are generally less stable than double bonds (e.g., N=C) and triple bonds (e.g., N≡C) because higher bond orders mean more shared electrons, leading to stronger bonds.
Evaluate electronegativity differences: A large difference in electronegativity between bonded atoms can lead to polar covalent bonds, which may be less stable than nonpolar covalent bonds.
Conclude that among the covalent bonds listed, N–C is likely the least stable due to its single bond nature, compared to the double bond N=C and the triple bond N≡C, which are stronger due to higher bond orders.