Multiple Choice
Draw the Lewis Dot Structure for POCl3.
4. Molecular Compounds
Lewis Dot Structures: Exceptions (Simplified)
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Draw the Lewis Dot Structure for the radical hydroxide, OH.
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Verified step by step guidance1
Identify the atoms involved in the hydroxide radical, OH. It consists of one oxygen (O) atom and one hydrogen (H) atom.
Determine the total number of valence electrons available. Oxygen has 6 valence electrons, and hydrogen has 1 valence electron, totaling 7 valence electrons.
Recognize that the hydroxide radical is a species with an unpaired electron, which means it will have an odd number of electrons.
Draw the oxygen atom with its 6 valence electrons as dots around it. Place the hydrogen atom next to the oxygen, sharing one electron to form a single bond.
Place the remaining unpaired electron on the oxygen atom, indicating the radical nature of the hydroxide ion. This results in a structure with a single bond between O and H, and one unpaired electron on oxygen.
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