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Multiple Choice
If the Kb of NH3 is 1.76 x 10-5, determine the acid dissociation constant of its conjugate acid.
A
1.08 x 10-10
B
5.68 x 10-10
C
5.68 x 10-9
D
1.0 x 10-14
Verified step by step guidance
1
Identify the relationship between the base dissociation constant (Kb) and the acid dissociation constant (Ka) for a conjugate acid-base pair. This relationship is given by the equation: \( K_w = K_a \times K_b \), where \( K_w \) is the ion-product constant of water, typically \( 1.0 \times 10^{-14} \) at 25°C.
Rearrange the equation to solve for the acid dissociation constant \( K_a \): \( K_a = \frac{K_w}{K_b} \).
Substitute the given values into the equation: \( K_a = \frac{1.0 \times 10^{-14}}{1.76 \times 10^{-5}} \).
Perform the division to calculate \( K_a \). This will give you the acid dissociation constant of the conjugate acid of NH3.
Compare the calculated \( K_a \) value with the provided options to determine the correct answer.