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Multiple Choice
Arrange the following molecules in order of decreasing dipole moment. H–I H–F H–Br H–Cl
A
H–Cl >H–I > H–Br > H–F
B
H–Br >H–Cl > H–F > H–I
C
H–F >H–Cl > H–Br > H–I
D
H–I >H–Cl > H–Br > H–F
Verified step by step guidance
1
Understand that the dipole moment of a molecule is determined by the difference in electronegativity between the atoms and the distance between them. The greater the difference in electronegativity, the larger the dipole moment.
Identify the electronegativities of the halogens involved: Fluorine (F) is the most electronegative, followed by Chlorine (Cl), Bromine (Br), and Iodine (I).
Recognize that the hydrogen-halogen bond with the greatest difference in electronegativity will have the largest dipole moment. Therefore, H-F will have the largest dipole moment because fluorine is the most electronegative.
Compare the remaining molecules: H-Cl, H-Br, and H-I. Since chlorine is more electronegative than bromine and iodine, H-Cl will have a larger dipole moment than H-Br and H-I.
Conclude the order of decreasing dipole moment based on electronegativity differences: H-F > H-Cl > H-Br > H-I.