Join thousands of students who trust us to help them ace their exams!Watch the first video
Multiple Choice
The reaction of potassium chlorate and sucrose is given below: If 2.33 x 10-7 formula units of potassium chlorate are reacted, how many grams of carbon dioxide will be produced?
A
3.94x10-16 g CO2
B
8.23x10-23 g CO2
C
2.72x10-21 g CO2
D
7.81x10-23 g CO2
E
2.55x10-29 g CO2
Verified step by step guidance
1
Identify the balanced chemical equation: 8 KClO3 + C12H22O11 → 8 KCl + 12 CO2 + 11 H2O. This tells us the stoichiometric relationship between reactants and products.
Determine the molar ratio between potassium chlorate (KClO3) and carbon dioxide (CO2) from the balanced equation. For every 8 moles of KClO3, 12 moles of CO2 are produced.
Convert the given number of formula units of KClO3 to moles. Use Avogadro's number (6.022 x 10^23 formula units/mol) to perform this conversion.
Use the stoichiometric ratio from step 2 to calculate the moles of CO2 produced from the moles of KClO3 obtained in step 3.
Convert the moles of CO2 to grams using the molar mass of CO2 (approximately 44.01 g/mol). This will give you the mass of CO2 produced.