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Multiple Choice
What is the specific gravity of lithium metal (in g/mL) at 10.0ºC if a cube measures 0.82 cm x 1.45 cm x 1.25 cm and has a mass of 0.794 g?
A
0.55
B
0.504
C
0.53
D
1.87
Verified step by step guidance
1
Calculate the volume of the lithium metal cube by multiplying its dimensions: Volume = 0.82 \text{ cm} \times 1.45 \text{ cm} \times 1.25 \text{ cm}.
Determine the density of the lithium metal by using the formula: Density = \frac{\text{mass}}{\text{volume}}. Use the mass given as 0.794 g and the volume calculated in the previous step.
Recall that specific gravity is the ratio of the density of a substance to the density of a reference substance, typically water at 4ºC, which has a density of 1 g/mL.
Since the density of water is 1 g/mL, the specific gravity of the lithium metal is numerically equal to its density in g/mL.
Use the density calculated in step 2 to express the specific gravity of lithium metal at 10.0ºC.