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Multiple Choice
Manganese (V) hydroxide has a measured solubility of 3.4×10–5 M at 25ºC. Calculate its Ksp value.
A
5.7×10–9
B
1.5×10–27
C
7.7×10–27
D
4.8×10–24
Verified step by step guidance
1
Identify the chemical formula for manganese (V) hydroxide, which is Mn(OH)_5.
Write the dissociation equation for Mn(OH)_5 in water: Mn(OH)_5 (s) ⇌ Mn^5+ (aq) + 5 OH^- (aq).
Define the solubility product constant (Ksp) expression for the dissociation: Ksp = [Mn^5+][OH^-]^5.
Recognize that the solubility of Mn(OH)_5 is given as 3.4×10^-5 M, which represents the concentration of Mn^5+ ions in solution.
Calculate the concentration of OH^- ions using the stoichiometry of the dissociation equation: [OH^-] = 5 × 3.4×10^-5 M. Substitute these values into the Ksp expression to find the Ksp value.