Join thousands of students who trust us to help them ace their exams!Watch the first video
Multiple Choice
Determine if each of the following compounds will create an acidic, basic or neutral solution. a) LiC2H3O2 b) C6H5NH3Br
A
a) acidic b) basic
B
a) acidic b) acidic
C
a) basic b) acidic
D
a) basic b) basic
Verified step by step guidance
1
Identify the ions present in each compound. For LiC2H3O2, the ions are Li+ and C2H3O2-. For C6H5NH3Br, the ions are C6H5NH3+ and Br-.
Determine the nature of each ion. Li+ is a cation from a strong base (LiOH), and C2H3O2- is the acetate ion, which is the conjugate base of acetic acid (a weak acid). C6H5NH3+ is the conjugate acid of aniline (a weak base), and Br- is the bromide ion, which is the conjugate base of hydrobromic acid (a strong acid).
Analyze the behavior of the ions in water. Li+ does not affect the pH significantly, while C2H3O2- can accept protons, making the solution basic. C6H5NH3+ can donate protons, making the solution acidic, while Br- does not affect the pH significantly.
Conclude the solution's nature based on the dominant ion effect. For LiC2H3O2, the basic nature of C2H3O2- dominates, resulting in a basic solution. For C6H5NH3Br, the acidic nature of C6H5NH3+ dominates, resulting in an acidic solution.
Summarize the findings: LiC2H3O2 creates a basic solution, and C6H5NH3Br creates an acidic solution.