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Multiple Choice
Calculate the pI of Arg. pKa1 = 9. pKa2 = 2.2. pKR = 12.5.
A
1.9
B
10.75
C
3.6
D
12.5
Verified step by step guidance
1
Identify the ionizable groups in arginine: the carboxyl group (pKa1 = 2.2), the amino group (pKa2 = 9.0), and the side chain guanidinium group (pKR = 12.5).
Determine the charge of arginine at different pH levels. At low pH, all groups are protonated, and as the pH increases, they lose protons in the order of their pKa values.
To find the isoelectric point (pI), identify the pH at which the molecule has a net charge of zero. For arginine, this occurs between the pKa values of the groups that lose protons to achieve a neutral charge.
Since arginine has a positively charged side chain, the pI is calculated using the average of the pKa values of the amino group and the side chain guanidinium group, which are the two groups that will be neutral at the pI.
Calculate the pI using the formula: pI = (pKa2 + pKR) / 2. Substitute the given values: pI = (9.0 + 12.5) / 2.