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1. Introduction to Biochemistry4h 34m
2. Water3h 23m
3. Amino Acids8h 10m
4. Protein Structure10h 4m
5. Protein Techniques14h 5m
6. Enzymes and Enzyme Kinetics13h 38m
7. Enzyme Inhibition and Regulation 8h 42m
8. Protein Function 9h 41m
9. Carbohydrates7h 49m
10. Lipids5h 49m
11. Biological Membranes and Transport 6h 37m
12. Biosignaling9h 45m
Review 1: Nucleic Acids, Lipids, & Membranes2h 47m
Review 2: Biosignaling, Glycolysis, Gluconeogenesis, & PP-Pathway3h 12m
Review 3: Pyruvate & Fatty Acid Oxidation, Citric Acid Cycle, & Glycogen Metabolism2h 26m
Review 4: Amino Acid Oxidation, Oxidative Phosphorylation, & Photophosphorylation1h 48m

2. Water

Biochemistry

2. Water

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Multiple Choice

Determine the pH of a solution with a [H⁺] of 2 x 10^-5 M.

pH = 2.2

pH = 4.7

pH = 10.9

pH = 6.1

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Verified step by step guidance

Understand that pH is a measure of the hydrogen ion concentration in a solution, and it is calculated using the formula: \( \text{pH} = -\log[\text{H}^+] \).

Identify the given hydrogen ion concentration, which is \([\text{H}^+] = 2 \times 10^{-5} \text{ M}\).

Apply the formula for pH: substitute the given \([\text{H}^+]\) value into the formula \( \text{pH} = -\log(2 \times 10^{-5}) \).

Use logarithmic properties to simplify the expression: \( \log(a \times b) = \log a + \log b \). Therefore, \( \log(2 \times 10^{-5}) = \log 2 + \log(10^{-5}) \).

Calculate \( \log 2 \) and \( \log(10^{-5}) \) separately, then add them together to find the pH value. Remember that \( \log(10^{-5}) = -5 \).