Table of contents

1. Introduction to Biochemistry4h 34m
2. Water3h 23m
3. Amino Acids8h 10m
4. Protein Structure10h 4m
5. Protein Techniques14h 5m
6. Enzymes and Enzyme Kinetics13h 38m
7. Enzyme Inhibition and Regulation 8h 42m
8. Protein Function 9h 41m
9. Carbohydrates7h 49m
10. Lipids5h 49m
11. Biological Membranes and Transport 6h 37m
12. Biosignaling9h 45m
Review 1: Nucleic Acids, Lipids, & Membranes2h 47m
Review 2: Biosignaling, Glycolysis, Gluconeogenesis, & PP-Pathway3h 12m
Review 3: Pyruvate & Fatty Acid Oxidation, Citric Acid Cycle, & Glycogen Metabolism2h 26m
Review 4: Amino Acid Oxidation, Oxidative Phosphorylation, & Photophosphorylation1h 48m

9. Carbohydrates

Hemiacetal vs. Hemiketal

Biochemistry

9. Carbohydrates

Hemiacetal vs. Hemiketal

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Multiple Choice

Use the image of the following glucose molecule to answer the questions.

A) Upon cyclization, which of the red circled carbons becomes the anomeric carbon?
a) A.
b) B.
c) C.
d) D.
e) E.
B) Upon cyclization, would a hemiacetal or hemiketal form?

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Verified step by step guidance

Identify the structure of glucose: Glucose is an aldohexose, meaning it has an aldehyde group and six carbon atoms.

Understand cyclization: In aqueous solutions, glucose can cyclize to form a ring structure. This involves the reaction between the aldehyde group and one of the hydroxyl groups.

Determine the anomeric carbon: The anomeric carbon is the carbon that was part of the carbonyl group (aldehyde or ketone) before cyclization. In glucose, this is the carbon that forms the new chiral center during ring formation.

Analyze the image: In the provided image, the carbon labeled 'E' is the one that has the double-bonded oxygen, indicating it is the carbonyl carbon. Upon cyclization, this carbon becomes the anomeric carbon.

Classify the type of cyclic structure: Since glucose is an aldose, the cyclization forms a hemiacetal. A hemiacetal is formed when an aldehyde reacts with an alcohol group.