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Multiple Choice
Which option below best describes the native gel electrophoresis migration for Proteins A, B, C & D (assuming equal mass & shape) considering that the buffer solution has a pH = 6.4. Protein A pI = 5.2, Protein B pI = 6.4, Protein C pI = 7.0, Protein D pI = 9.2
A
A & B will migrate to the negative pole while C & D migrate to the positive pole.
B
A will migrate to the positive pole, B will not migrate, while C & D migrate to the negative pole.
C
A & B will migrate to the positive pole while C & D migrate to the negative pole.
D
A will migrate to the negative pole, B will not migrate, while C & D migrate to the positive pole.
Verified step by step guidance
1
Understand the concept of isoelectric point (pI): The isoelectric point is the pH at which a protein carries no net charge. At a pH below its pI, a protein will carry a positive charge, and at a pH above its pI, it will carry a negative charge.
Determine the charge of each protein at pH 6.4: Compare the pH of the buffer (6.4) with the pI of each protein to determine their net charge.
Analyze Protein A: Since the pI of Protein A is 5.2, which is less than 6.4, Protein A will have a negative charge and migrate towards the positive pole.
Analyze Protein B: The pI of Protein B is 6.4, which is equal to the pH of the buffer. Therefore, Protein B will have no net charge and will not migrate.
Analyze Proteins C and D: Protein C has a pI of 7.0, and Protein D has a pI of 9.2. Both are greater than 6.4, so they will have a positive charge and migrate towards the negative pole.