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Multiple Choice
Considering the Lineweaver-Burk plot below, which of the following enzymes would be better to use (converts more substrate to product) when the [S] = 0.001 M?
A
Enzyme A
B
Enzyme B
Verified step by step guidance
1
Understand the Lineweaver-Burk plot: This plot is a double reciprocal graph of the Michaelis-Menten equation, where the y-axis represents \( \frac{1}{V_0} \) (the reciprocal of the initial velocity) and the x-axis represents \( \frac{1}{[S]} \) (the reciprocal of the substrate concentration).
Identify the lines for Enzyme A and Enzyme B: The plot shows two lines, one for each enzyme. The slope of each line is equal to \( \frac{K_m}{V_{max}} \), and the y-intercept is \( \frac{1}{V_{max}} \).
Determine \( V_{max} \) for each enzyme: The enzyme with the lower y-intercept has a higher \( V_{max} \), meaning it can convert more substrate to product at saturation. Compare the y-intercepts of Enzyme A and Enzyme B.
Evaluate the slope for each enzyme: The slope of the line is indicative of \( K_m \). A lower slope suggests a lower \( K_m \), which means the enzyme is more efficient at lower substrate concentrations.
Decide which enzyme is better at \( [S] = 0.001 \) M: At low substrate concentrations, the enzyme with the lower \( K_m \) (lower slope) will be more efficient. Compare the slopes of Enzyme A and Enzyme B to determine which enzyme is better suited for the given substrate concentration.