Draw structures corresponding to the following aldehyde and ketone names:
e. 1,1,1-Trichloro-3-pentanone

Question

Draw structures corresponding to the following aldehyde and ketone names:

e. 1,1,1-Trichloro-3-pentanone

Accepted Answer

Hi, everyone. Our next question asks, what is the correct structure for the following ketone? And we're given the name 11 Di Chloro Hexane to own. So let's think about how we go about drawing a structure given an Iupac name like this. So we start by finding what is the root that tells us what is the length of the longest carbon chain of our molecule. So in this case, that's going to be that Hexane. So I'm gonna highlight that in blue that tells us that we have six carbons in our chain, longest chain. So I'm going to go ahead and draw that in the form of a skeletal structure. So that kind of zigzag shape. So 123456, it's always good to double check, count those carbons. Again, it's very easy to accidentally leave off one or add an extra carbon when drawing a skeletal structure. So I'm going to go ahead and add numbers to this 123456. So I definitely have six carbons and that will help me when I go to add my substituents since I have them numbered. So now I'll look at the ending of my root word I have that hexane and then it ends in two own. So highlight that in red. Well, my problems already told me that I have a ketone and this tells me that the carbon carbon is carbon two. So I'm going to erase this number two to make room and to carbon two, I will be adding that double bond to an oxygen. So that's my carbonel group that makes this a ketone. And then finally, I look at the first part of my name with the prefix here, I'll highlight in yellow that tells me which substituents I have and where they're located. So in this case, 11 di chloro. So I know I have two chlorine and that they're both attached to carbon one. So I erase my little number one, I will extend another bond from carbon one, 21 chlorine Adam and then a second line going down from carbon went with a second chlorine. So now I'll raise the rest of my numbers to have my structure. And I have the structure for this ketone, which is a six carbon chain where I have two chlorine atoms on carbon one and my carbonel group. So a double bond to an oxygen on carbon two. See you in the next video.

Draw structures corresponding to the following aldehyde and ketone names:
e. 1,1,1-Trichloro-3-pentanone

Verified video answer for a similar problem:

Key Concepts

Aldehydes and Ketones

Nomenclature

Structural Representation

Draw structures corresponding to the following aldehyde and ketone names:e. 1,1,1-Trichloro-3-pentanone

Verified video answer for a similar problem:

Key Concepts

Aldehydes and Ketones

Nomenclature

Structural Representation

Draw structures corresponding to the following aldehyde and ketone names:
e. 1,1,1-Trichloro-3-pentanone